How Does the Millikan Oil Drop Experiment Illustrate the Balance of Forces?

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SUMMARY

The Millikan Oil Drop Experiment demonstrates the balance of forces acting on an oil drop with a mass of 7.20 x 10^-16 kg moving at a constant speed of 2.50 m/s in an electric field of 2.20 x 10^4 V/m. The net force acting on the drop is zero, indicating that the electric force (Fe) equals the gravitational force (Fg). The charge on the oil drop is calculated using the formula q = mg/E, resulting in a magnitude of 3.2 x 10^-19 C. This experiment effectively illustrates the concept of equilibrium in the context of electric and gravitational forces.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational force (Fg = mg)
  • Familiarity with electric force (Fe = qE)
  • Concept of electric field strength (E = V/d)
NEXT STEPS
  • Study the principles of electrostatics and electric fields in detail.
  • Explore the derivation and applications of Newton's laws of motion.
  • Investigate the historical context and significance of the Millikan Oil Drop Experiment.
  • Learn about the implications of charge quantization in physics.
USEFUL FOR

Students in physics, educators teaching electromagnetism, and anyone interested in understanding the principles of force balance in charged particles.

General_Sax
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Homework Statement


An oil drop with a mass of 7.20*10^-16kg moves upward at a constant speed of 2.50 m/s between two horizontal, parallel plates. If the electric field strength between these plates is 2.20*10^4 V/m, what is the magnitude of the charge on the oil drop?


Homework Equations


F = ma
Fg = mg
Fe = qE
E = V/d


The Attempt at a Solution


F = ma
F = m(0)
Fnet = 0

Fnet = Fe - Fg
Fg = Fe
q = mg/E

q = 3.2*10^-19C

My problem is conceptual. I don't really understand how the particle can have a constant velocity and a net Force of zero upon it.

How did the particle accelerate from stationary to it's current velocity?
 
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The history of the particle isn't all that important. The mention of constant velocity is to reinforce the idea that it is not accelerating, and hence no net force.
 

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