Proving Minimization of Helmholtz Free Energy at Equilibrium

Click For Summary
SUMMARY

The discussion focuses on proving that the Helmholtz Free Energy (F) is minimized at equilibrium for a reaction occurring at constant temperature (T) and volume (V). The relevant equations include F = U - TS and the differential form dF = dU - TdS - SdT. The solution involves showing that at equilibrium, dF simplifies to μdN, indicating that changes in the number of particles (N) affect the free energy. Additionally, the second derivative test is necessary to confirm that F is indeed minimized, rather than maximized or at a saddle point.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically Helmholtz Free Energy
  • Familiarity with the first and second laws of thermodynamics
  • Knowledge of differential calculus in the context of thermodynamic equations
  • Basic principles of chemical potential and its role in chemical reactions
NEXT STEPS
  • Study the derivation of Helmholtz Free Energy and its applications in thermodynamics
  • Learn about the second derivative test in thermodynamic contexts
  • Research the relationship between chemical potential and equilibrium in multi-species reactions
  • Explore the implications of constant temperature and volume on thermodynamic systems
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying chemical reactions and equilibrium conditions, as well as researchers focusing on energy minimization principles in physical chemistry.

Silviu
Messages
612
Reaction score
11

Homework Statement


Show that for a reaction occurring at constant T and V, F is minimized at equilibrium.

Homework Equations


##F=U-TS##
##TdS=dU+pdV-\mu dN##

The Attempt at a Solution


##dF=dU-d(TS)=dU-TdS-SdT=dU-dU -pdV+ \mu dN -S dT=-pdV - SdT + \mu dN##. At constant T and V this reduces to ##dF = \mu dN##. But I don't know what to do from here. Also in the next problem we have to use the fact that F is minimized at equilibrium to prove a relation between the chemical potentials of certain elements involved in a chemical reaction, so I assume i can't set ##dN=0##, as in a chemical reaction N changes and it seems that the fact that F is minimal at equilibrium holds in chemical reactions, too.
How can I solve this? Thank you!
 
Physics news on Phys.org
When multiple species exist, the last term must be ##\Sigma\mu_i \,dN_i##, no? That's quite different from ##\mu\,dN## in the context of your problem.

Then, you have to prove that ##F## is minimized rather than maximized or at a saddle point. Use the second derivative to do this.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K