Minimum deaceleration untll the car stops

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SUMMARY

The discussion centers on calculating the minimum deceleration required for a car traveling at 25 miles per hour to stop within a 35-meter-long shoulder. The correct formula to use is a = v² / (2x), where 'v' is the velocity in meters per second and 'x' is the stopping distance. Participants emphasized the importance of accurately converting 25 miles per hour to meters per second, using the conversion factor of 1 mile = 1.6 kilometers and 1 hour = 3600 seconds. The miscalculation of the initial velocity conversion led to erroneous results.

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forensicchemgirl
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what am i doing wrong??
every time i try to answer this i get t=.2s and a=-1651ms^-2

the problem reads...
A car traveling at 25mi/h is to stop on a 35m-long shoulder of the road. (a) What is the required magnitude of he minimum acceleration? (b)How much time will elapse during this minimum deaceleration untll the car stops.

i used the equation...
a=v^2/2x



 
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i think the first time is to convert 25mi/h into meters per second.

~Amy
 
Yes, use 1 mile =1.6km, and don't forget to convert to m/s, so you need to change out of km/h. 1h=3600s. That equation is right.
 
yes i did convert to m/s wrong thanks for the help.:smile: :-p
 

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