Minimum MSE estimation derivation

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EmmaSaunders1
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Hello,

Would anyone be-able to recommend a good, easy to read article which outlines MMSE and its derivation. Specifically I am having trouble finding this term


[tex] + \int x'xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2[/tex]

from

[tex] E({\left | \left | X-z \right | \right |}^2|Y=y)<br /> =\int (x-z)'(x-z)P(x|y)dx\\<br /> =[z'-\int x'P(x|y)dx][z-\int xP(x|y)dx] + \int x'xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2[/tex]

Thank you
 
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Shouldnt the term just be zero - I can't understand it's presence - are there any conditions in which it is not zero??
 
For anyone who is interested - the last term

[tex] + \int x'xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2[/tex]

is necessary to account for the difference between E(x^2) and [E(x)]^2. When Z = E[x|Y=y] the term

[tex] E({\left | \left | X-z \right | \right |}^2|Y=y)[/tex]

Is a minimum and reduces to

[tex] + \int x'xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2 = [/tex]

Then

[tex] E({\left | \left | X \right | \right |}^2|Y=y)-E(X|Y=y)^2\\<br /> =E({\left | \left | X \right | \right |}^2|Y=y)-{\left | \left | \hat{X} \right | \right |}^2[/tex]

which is the average mean square error