Minimum MSE estimation derivation

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SUMMARY

The discussion focuses on the derivation of Minimum Mean Square Error (MMSE) estimation, specifically addressing the term + ∫ x'xP(x|y)dx - || ∫ xP(x|y)dx ||^2. This term is crucial for understanding the difference between E(x^2) and [E(x)]^2. The participants clarify that when Z = E[x|Y=y], the expression for E(||X-z||^2|Y=y) reaches its minimum, confirming the necessity of the discussed term in MMSE calculations.

PREREQUISITES
  • Understanding of Minimum Mean Square Error (MMSE) estimation
  • Familiarity with conditional probability distributions, specifically P(x|y)
  • Knowledge of mathematical expectations and variance concepts
  • Proficiency in calculus, particularly integration techniques
NEXT STEPS
  • Study the derivation of MMSE in detail using resources like "Statistical Estimation Theory"
  • Explore the implications of conditional expectations in probability theory
  • Learn about the properties of variance and how they relate to MMSE
  • Investigate applications of MMSE in machine learning and signal processing
USEFUL FOR

Statisticians, data scientists, and researchers in fields requiring estimation theory, particularly those focused on minimizing error in predictive models.

EmmaSaunders1
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Hello,

Would anyone be-able to recommend a good, easy to read article which outlines MMSE and its derivation. Specifically I am having trouble finding this term


<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

from

<br /> E({\left | \left | X-z \right | \right |}^2|Y=y)<br /> =\int (x-z)&#039;(x-z)P(x|y)dx\\<br /> =[z&#039;-\int x&#039;P(x|y)dx][z-\int xP(x|y)dx] + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

Thank you
 
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Shouldnt the term just be zero - I can't understand it's presence - are there any conditions in which it is not zero??
 
For anyone who is interested - the last term

<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

is necessary to account for the difference between E(x^2) and [E(x)]^2. When Z = E[x|Y=y] the term

<br /> E({\left | \left | X-z \right | \right |}^2|Y=y)<br />

Is a minimum and reduces to

<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2 = <br />

Then

<br /> E({\left | \left | X \right | \right |}^2|Y=y)-E(X|Y=y)^2\\<br /> =E({\left | \left | X \right | \right |}^2|Y=y)-{\left | \left | \hat{X} \right | \right |}^2<br />

which is the average mean square error
 

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