Minimum of Tan^p + Cot^q for 0 < x < Pi/2

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Discussion Overview

The discussion revolves around finding the minimum value of the expression \( y = \tan(x)^p + \cot(x)^q \) for positive rational numbers \( p \) and \( q \) within the interval \( 0 < x < \frac{\pi}{2} \). The conversation touches on aspects of trigonometry and calculus, with participants exploring different approaches to the problem.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant suggests setting \( u = \tan(x) \) to reformulate the problem, leading to the expression \( y = u^p + (1/u)^q \).
  • Another participant points out that the condition \( 0 < x < \frac{\pi}{2} \) has not been utilized effectively in the discussion.
  • There is a mention of a book that discusses trigonometry without calculus, indicating a potential disconnect in the expected approach to the problem.
  • A participant expresses uncertainty about how to tackle the problem using trigonometry alone.
  • One participant provides a transformation of the original expression into a form involving sine and cosine, suggesting a potential pathway for analysis.
  • A later reply questions whether the minimum has been correctly identified, hinting at the complexity of the problem.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best approach to solve the problem, and multiple competing views remain regarding the application of calculus versus trigonometry.

Contextual Notes

There is a lack of clarity regarding the application of the condition \( 0 < x < \frac{\pi}{2} \) in the context of the problem, and the discussion reflects uncertainty about the appropriate mathematical tools to use.

hadi amiri 4
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suppose p and q are positive rational numbers with the condition : 0<x<Pi/2
find the minimum y=Tan(x)^p+Cot(x)^q
 
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Well set u=Tan(x),
Hence, y=u(x)^p+(1/u)^q, along with [tex]\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}[/tex]
should settle it nicely.
 
you did not use the condition
 
hadi amiri 4 said:
you did not use the condition

Hi hadi! :smile:

arildno left that to you!

If 0 < x < π/2, and u = tanx, then the condition on u is … ? :smile:
 
i found this problems in a book which was just talking about trigonometry and that book was empty of calculus
 
hadi amiri 4 said:
i found this problems in a book which was just talking about trigonometry and that book was empty of calculus

ah … you put this in the Calculus & Analysis sub-forum, so we assumed you wanted a calculus answer! :smile:

I really have no idea how to do this with trignonometry. :redface:
 
you are right
 
please tell me where is the appropriate sub-forum
 
  • #10
[tex]tan(x)= \frac{sin(x)}{cos(x)}[/tex]
and
[tex]cot(x)= \frac{cos(x)}{sin(x)}[/tex]
so
[tex]tan^p(x)+ cot^q(x)= \frac{sin^p(x)}{cos^p(x)}+ \frac{cos^q(x)}{sin^q(x)}= \frac{sin^{p+q}(x)+ cos^{p+q}(x)}{sin^q(x)cos^p(x)}[/tex]
 
  • #11
Are you sure that you have found the minimum of this problem?
or changing tan to sin/cos and ...
 

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