- #1

karush

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$\displaystyle \int_0^{\pi/2}\sin (x^2)\ dx$

ok think this should be area not volume but hope my int is set up ok

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- MHB
- Thread starter karush
- Start date

- #1

karush

Gold Member

MHB

- 3,267

- 4

$\displaystyle \int_0^{\pi/2}\sin (x^2)\ dx$

ok think this should be area not volume but hope my int is set up ok

- #2

skeeter

- 1,104

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Is this a volume of rotation with respect to a given axis of rotation, or is it a volume

of similar cross sections whose base lies in a region defined by the given curve,

or … something else?

- #3

HallsofIvy

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