Minimum speed of the bullet to penetrate a sphere

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Homework Help Overview

The problem involves determining the minimum speed of a bullet with mass m and charge q required to penetrate a solid uniformly charged sphere of radius R and total charge +q. The scenario considers only electrostatic forces, neglecting any resistance or friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss two main approaches: conservation of energy and the work-energy theorem. There is a focus on whether the initial setup and equations are correctly formulated, particularly regarding the signs in the work-energy equation.

Discussion Status

Some participants have confirmed the validity of the approaches presented, while others have raised concerns about potential sign errors in the equations. The discussion appears to be productive, with participants actively engaging in clarifying the mathematical details.

Contextual Notes

Participants are considering the implications of the electric field's behavior within the sphere and how it affects the bullet's motion. There is an acknowledgment of the need to ensure the correct application of physical principles in the context of the problem.

Tanya Sharma
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Homework Statement



A bullet of mass m and charge q is fired towards a solid uniformly charged sphere of radius R and total charge + q. If it strikes the surface of sphere with speed u, find the minimum speed u so that it can penetrate through the sphere. (Neglect all resistance forces or friction acting on bullet except electrostatic forces)

Homework Equations


The Attempt at a Solution



I think if the bullet can just reach the center ,then it can penetrate through the sphere because the electric field inside a sphere is radially outwards .As it reaches the center and moves just a little bit outwards radially ,the electric field will push the bullet outwards .

The problem can be approached either by conservation of energy or by work kinetic energy theorem.

1) By conservation of energy

kq2/R+(1/2)mu2 = (3/2)kq2/R

2) By work energy theorem

## \int_{R}^{0}\frac{kq^{2}r}{R^3} \hat{r} \cdot dr\hat{r} = \frac{1}{2}mu^2 ##

Have I approached the problem correctly or is there something more in it ?
 
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Both approaches look correct to me.

But in the work energy equation, there might be a sign problem. I think your integral on the left is correct for the work done by the electric force on the bullet as it goes from the surface to the center. But, is the sign correct on the right for the change in KE?
 
Yes.. you are right.There should be a minus sign in the LHS .

Thanks TSny...

Would you mind having a look at the other thread :"flux through a circular ring " .
 
Tanya Sharma said:
Yes.. you are right.There should be a minus sign in the LHS .

Thanks TSny...

Would you mind having a look at the other thread :"flux through a circular ring " .

I'll take a look tomorrow. It's that time again. :zzz:
 
Okay :smile:
 

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