I Minkowski Spacetime KVF Symmetries

Click For Summary
Minkowski spacetime possesses 10 independent Killing Vector Fields (KVFs), derived from its isometries, which include 4 translations and 6 rotations. A KVF is defined by the condition that the Lie derivative of the metric tensor along it vanishes, indicating symmetry in the spacetime. The discussion clarifies that while any linear combination of the KVFs remains a KVF, a generic smooth vector field may not satisfy this condition due to non-constant coefficients. The relationship between the Lie derivative and the metric structure is emphasized, noting that only specific vector fields derived from the Killing equation qualify as KVFs. Ultimately, Minkowski spacetime exemplifies maximum symmetry, represented by the Poincare group, which encompasses both translations and Lorentz transformations.
  • #31
Orodruin said:
$$
\mathcal L_\xi T = \lim_{s\to 0}[(\phi_{s\xi}^*T - T)/s].
$$ As the pullback defines a map between different points in the manifold, we are not in need of a connection in order to compute the Lie derivative.
A doubt about the limit involved in the Lie derivative defintion. At first sight that limit makes sense when we pick a chart in the differentiable atals and do the calculation there. Does it imply a notion of limit from an invariant coordinate-free point of view ?
 
Physics news on Phys.org
  • #32
Sure, this is a definition completely independent of any choice of coordinates. Since all the manipulations used to define the limit are manifestly covariant, it maps the arbitrary tensor field ##T## to another tensor field of the same rank.
 
  • #33
vanhees71 said:
Sure, this is a definition completely independent of any choice of coordinates. Since all the manipulations used to define the limit are manifestly covariant
Ah ok, indeed the operations involved in the definition are part of tensor space structure that exist at each point of the manifold. Namely a difference between (0,2) tensors defined at the same point (i.e. elements of the same tensor space) and a scalar multiplication for ##1/s##.
 
Last edited:

Similar threads

  • · Replies 23 ·
Replies
23
Views
1K
Replies
22
Views
2K
  • · Replies 1 ·
Replies
1
Views
938
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 51 ·
2
Replies
51
Views
5K
  • · Replies 26 ·
Replies
26
Views
2K