Missing gravity and kinetic friction

[randomss444]

Homework Statement

What is the network done on the car during the time interval?

Mass = 75,000kg
Vi = 0
vf = 111.11m/s^2
t = 2.5s
∆x = 138.8875m

Homework Equations

W= F∆X

∆KE = (1/2)(m)(v)^2

W = ∆KE

The Attempt at a Solution

∆KE = 1/2(75000kg)(111.11m/s)^2
∆KE = 463953703.8j

And since W=∆KE
W = 463953703.8j

Is this right? I am wondering if I am missing gravity and kinetic friction somewhere?

Thanks

 

[kuruman]

Your method of calculation is correct - I did not plug in the numbers to see if you did that part correctly. I cannot help wondering what kind of car has mass 75,000 kg (75 tons) and is able to go from zero to 111 m/s (250 miles per hour) in 2.5 s.