Pulling masses up a tilted plane with kinetic friction

In summary, kinetic friction makes it more difficult to pull masses up a tilted plane by opposing the applied force. The magnitude of kinetic friction is influenced by the coefficient of friction, weight of the masses, and angle of the incline. The force needed to pull masses up a tilted plane with kinetic friction can be calculated using the equation F = μk * m * g * sinθ. To reduce the effect of kinetic friction, lubricants can be used or the weight of the masses can be decreased. The angle of the incline also affects the force needed, with steeper inclines resulting in a greater force of friction.
  • #1
jamiebean
55
3
Homework Statement
attached below
Relevant Equations
N= mg
螢幕截圖 2020-05-22 下午8.29.37.png


first, i calculated the kinetic friction:
0.77 x (weight of the 2 boxes x 9.8)= 55.16N

then i calculated the angle of the triangle:
tan^-1(2.5/4.75)=27.758

IMG-0945.jpg


then i drew this

then i used sine to find out force 3 which is 33.3556

so the final force needed is 33.3556 + kinetic friction= 88.516

is this correct?
 
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  • #2
My numbers disagree with yours. Since you do not provide the equations in which you substituted the numbers, I cannot check the details of where you went wrong. The statement
jamiebean said:
then i used sine to find out force 3 which is 33.3556
is not informative enough. Please post a more complete solution.
 
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