Pulling masses up a tilted plane with kinetic friction

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SUMMARY

The discussion focuses on calculating the forces involved in pulling two boxes up a tilted plane with kinetic friction. The kinetic friction was calculated as 55.16 N using a coefficient of friction of 0.77 and the weight of the boxes. The angle of the incline was determined to be 27.758 degrees using the tangent function. The total force required to overcome both the incline and kinetic friction was found to be 88.516 N, which includes an additional force of 33.3556 N derived from sine calculations. The accuracy of these calculations is questioned due to a lack of detailed equations.

PREREQUISITES
  • Understanding of kinetic friction calculations
  • Knowledge of trigonometric functions, specifically sine and tangent
  • Familiarity with Newton's second law of motion
  • Basic principles of inclined planes in physics
NEXT STEPS
  • Review the principles of kinetic friction and its calculation methods
  • Study trigonometric functions and their applications in physics problems
  • Learn about Newton's laws and their relevance to forces on inclined planes
  • Explore detailed examples of force calculations on inclined planes with friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the dynamics of forces on inclined planes with friction.

jamiebean
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Homework Statement
attached below
Relevant Equations
N= mg
螢幕截圖 2020-05-22 下午8.29.37.png


first, i calculated the kinetic friction:
0.77 x (weight of the 2 boxes x 9.8)= 55.16N

then i calculated the angle of the triangle:
tan^-1(2.5/4.75)=27.758

IMG-0945.jpg


then i drew this

then i used sine to find out force 3 which is 33.3556

so the final force needed is 33.3556 + kinetic friction= 88.516

is this correct?
 
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My numbers disagree with yours. Since you do not provide the equations in which you substituted the numbers, I cannot check the details of where you went wrong. The statement
jamiebean said:
then i used sine to find out force 3 which is 33.3556
is not informative enough. Please post a more complete solution.
 

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