Pulling masses up a tilted plane with kinetic friction

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jamiebean
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Homework Statement
attached below
Relevant Equations
N= mg
螢幕截圖 2020-05-22 下午8.29.37.png


first, i calculated the kinetic friction:
0.77 x (weight of the 2 boxes x 9.8)= 55.16N

then i calculated the angle of the triangle:
tan^-1(2.5/4.75)=27.758

IMG-0945.jpg


then i drew this

then i used sine to find out force 3 which is 33.3556

so the final force needed is 33.3556 + kinetic friction= 88.516

is this correct?
 
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My numbers disagree with yours. Since you do not provide the equations in which you substituted the numbers, I cannot check the details of where you went wrong. The statement
jamiebean said:
then i used sine to find out force 3 which is 33.3556
is not informative enough. Please post a more complete solution.