Mixed State Treatment: Eigenvalue Degeneracy

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jk22
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Suppose i have an eigenvalue which is two fold degenerate-. Is it possible to have a density matrix formulation for the following : there is a continuum of states considered namely every state in the eigenspace.

How would it be written : $$\sum_{\lambda}\int \rho (\lambda,\alpha)|\lambda, \alpha\rangle\langle \lambda, \alpha|d\alpha $$ ?
 
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Thanks. What I would like to know is if it is possible to treat every vector in the eigenspace separately ?

My other question is : since the temperature is never 0K the endstate in a measurement of a multiple eigenvalue is a mixed state. In fact there never exist pure state at non zero temperature ?
 
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States with definite energy usually are intrisically mixed states unless there are other conserved quantities that allow one to split the eigenspace into smaller invariant subspaces.

jk22 said:
In fact there never exist pure state at non zero temperature ?
Yes. By definition, a state at fixed positive temperature has a density matrixof the form ##e^{-S/\kbar}## with an operator $S$ whose expectation is the entropy.

Most states in nature are mixed; only systems with very few degrees of freedom can be prepared in a pure state.