Mixing Alcohol Solutions: Calculating the Percentage of a New Solution

[Jameson]

6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The percentage alcohol in the new solution is ___________?
--------------------

 

[Jameson]

Congratulations to the following members for their correct solutions:

1) Reckoner
2) Sudharaka

Solution (from Sudharaka):

[sp]The number of pints of alcohol in the first solution \(\displaystyle=6\times\frac{20}{100}=\frac{6}{5} \) The number of pints of alcohol in the second solution \(\displaystyle=4\times\frac{10}{100}=\frac{2}{5} \)The percentage of alcohol in the new solution \(\displaystyle=\frac{\frac{6}{5}+\frac{2}{5}}{10}\times 100=\frac{8}{5}\times 10=16\%\)[/sp]