Mixture to create a 50% acid solution?

[mathdad]

How many milliliters of a 10% acid solution must be added to 55 milliliters of a 80% acid solution to create a 50% acid solution?

This is my equation set up:

0.10x + 55(0.80) = 0.50(x + 55)

Is this correct?

 

[MarkFL]

Yes, you have the amount of acid (in mL) on both sides of the equation. (Yes)

 

[mathdad]

Yes, you have the amount of acid (in mL) on both sides of the equation. (Yes)

All I have to do is solve for x, right?

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I got x = 41.25.Is this right?

 

[Joppy]

All I have to do is solve for x, right?

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I got x = 41.25.Is this right?

Mathematically, yes.

 

[mathdad]

Mathematically, yes.

Ok. So, the answer is 41.25 milliliters of a 10% acid solution. Does this even make sense? Why is this answer for milliliters a decimal number while the given milliliter is 55, a whole number? See my point?