Modeling Applications and Diff EQs

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neshepard
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Homework Statement


A certain virus spreads through an entire population of 1000. It is assumed that the virus spreads at a rate proportional to the product of the infected and the uninfected. k=.00005 and initial infected is 250. Write and solve the diff eq for this problem.


Homework Equations


I used dP/dt=kP(1-P/L) where P=infected population, L=1000 carrying capacity, k=constant



The Attempt at a Solution


dP/dt=.00005P(1-P/1000)
dP/P(1-P/1000)=.00005dt and integrate both sides to get
P(t)=1000/1+3e^-.00005t

Is this correct? Maybe I'm just tired, but looking at it seems weird somehow.
 
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It's correct up to some parentheses you left out.
 
P(t)=1000/(1+3e^-.00005t) are these the parentheses you mean?

Thanks
 
neshepard said:
P(t)=1000/(1+3e^-.00005t) are these the parentheses you mean?

Thanks

Almost, I'd put parenthesis around the exponent as well

P(t)=1000/(1+3e^(-.00005t))

It's much easier to read that way.
 
Thanks. Staring to long at this.