System of diff eqs modeling salt in tanks

Click For Summary
SUMMARY

The discussion revolves around a system of differential equations modeling the flow of saltwater in three interconnected tanks. The equations are defined as dA/dt = -0.02A, dB/dt = 0.01A - 0.04B, and dC/dt = 0.01A + 0.04B, with initial conditions A(0)=1000, B(0)=0, and C(0)=0. Participants express confusion regarding the flow rates between tanks A, B, and C, particularly questioning why the outflow rates are not equal and why dC/dt is represented as a sum rather than a difference. The discussion emphasizes the need for clarity on the flow dynamics and assumptions regarding tank capacities.

PREREQUISITES
  • Understanding of differential equations, specifically first-order linear equations.
  • Familiarity with fluid dynamics concepts, particularly flow rates and mixing processes.
  • Knowledge of initial value problems and their applications in modeling real-world systems.
  • Basic principles of systems of equations and their graphical representations.
NEXT STEPS
  • Research the application of differential equations in fluid dynamics, focusing on systems with multiple tanks.
  • Learn about the method of solving initial value problems in differential equations.
  • Explore the concept of flow rates in interconnected systems and how they affect concentration changes.
  • Study graphical methods for visualizing solutions to systems of differential equations.
USEFUL FOR

Students and professionals in engineering, environmental science, and applied mathematics who are interested in modeling fluid systems and understanding the dynamics of interconnected tanks.

nate9519
Messages
47
Reaction score
0
1. The problem

dA/dt = -.02A
dB/dt = .01A - .04B
dC/dt = .01A + .04B

A(0)=1000
B(0)=0
C(0)=0Come up with a sketch and a word problem involving three tanks for which the system of differential equations with initial conditions above applies. Have fresh water flowing into tank A, with the volumes of brine in B and C remaining constant. Assume that the third tank has such capacity that it would not overflow during the time period under consideration. Use different values for the amounts of brine in tanks B and C (for example 1,000 gallons in tank B and 2,000 gallons in tank C [PS : don't use 1000 and 2000])

2. equations
n/a

3. Attempt at solution

Can someone help me interpret this problem. there are multiple aspects of this system that don't make sense to me. first is that if A flows into B then the rate out of A should be equal to the rate in for B. but instead it is half (.02A in dA/dt and .01A in dB/dt). and I also don't understand why dC/dt is a sum instead of a difference. If rate of change is rate in minus rate out then why is dC/dt a sum?
 
Physics news on Phys.org
nate9519 said:
1. The problem

dA/dt = -.02A
dB/dt = .01A - .04B
dC/dt = .01A + .04B

A(0)=1000
B(0)=0
C(0)=0Come up with a sketch and a word problem involving three tanks for which the system of differential equations with initial conditions above applies. Have fresh water flowing into tank A, with the volumes of brine in B and C remaining constant. Assume that the third tank has such capacity that it would not overflow during the time period under consideration. Use different values for the amounts of brine in tanks B and C (for example 1,000 gallons in tank B and 2,000 gallons in tank C [PS : don't use 1000 and 2000])

2. equations
n/a

3. Attempt at solution

Can someone help me interpret this problem. there are multiple aspects of this system that don't make sense to me. first is that if A flows into B then the rate out of A should be equal to the rate in for B. but instead it is half (.02A in dA/dt and .01A in dB/dt). and I also don't understand why dC/dt is a sum instead of a difference. If rate of change is rate in minus rate out then why is dC/dt a sum?

Think about the possibility that A flows into both B and C. What else must flow into C? And who said C has any outflow at all?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
3
Views
3K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K