Mol Ratio of Na2CO3 + HCl Reaction

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SUMMARY

The molar ratio of sodium carbonate (Na2CO3) to hydrochloric acid (HCl) in the reaction is 1:2, as established by the balanced chemical equation Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l). This indicates that one mole of Na2CO3 reacts with two moles of HCl. Understanding this ratio is crucial for stoichiometric calculations in titration experiments.

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Im a beginner in chemistry and i just did a chemistry lab with my class on titration.
Na2CO3(s) + 2HCl(aq)==>2NaCl(aq) + CO2(g) + H2O(l)
Can any1 tell me what the mol ratio is for this equation?
 
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The balanced equation tells you the mole ratio. eg. You know that 1 mole of Na2CO3 reacted with 2 moles of HCL
 

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