Molarity, Molality & Mole Fraction Calculations for Glycerol-Water Solution

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SUMMARY

The discussion focuses on calculating the molarity, mole fraction, and molality of a glycerol-water solution with equal masses of glycerol (C3H8O3) and water, having a density of 1.10 g/mL. To find the molarity, the formula M = moles of solute/liters of solution is applied, alongside the mole fraction formula, mole fraction = n1/n(total), and the molality formula, molality = moles of solute/kg of solvent. The calculations begin with determining the moles of glycerol and water based on their equal masses and the total volume of the solution.

PREREQUISITES
  • Understanding of molarity calculations
  • Familiarity with mole fraction and molality concepts
  • Knowledge of density and its application in solution calculations
  • Ability to perform conversions between grams, moles, and liters
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  • Calculate the molarity of a glycerol-water solution using varying densities
  • Explore the impact of temperature on the density of glycerol-water mixtures
  • Learn about the colligative properties of solutions with glycerol
  • Investigate the role of glycerol in biological systems and its concentration effects
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Chemistry students, educators, and professionals involved in solution chemistry, particularly those working with glycerol and water mixtures in laboratory or industrial settings.

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Homework Statement


A solution containing equal masses of glycerol, C3H8O3, and water has a density of
1.10 g/mL. Calculate the (a) molarity; (b) mole fraction of glycerol; (c) molality of
the solution.

Homework Equations


M=moles of solute/liters of solution
mole fraction = n1/n(total)
molality = mole of solute/kg of solvent

The Attempt at a Solution


How do you calculate the moles? i think i got the liters of solution by doing this: molar mass of gycerol/density. then convert the mL to L.
 
Physics news on Phys.org
You are told "equal masses". That means every substance mass is a third of the solution mass. Start with 1 liter.
 

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