Moles of Potassium Alum in 2KAl(SO_4)_2 * 12H_2O

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Discussion Overview

The discussion revolves around the interpretation of the chemical formula for Potassium Alum, specifically 2KAl(SO4)2 * 12H2O, and how it relates to the number of moles of Potassium Alum and Aluminum involved in a reaction. Participants explore the implications of the formula in terms of stoichiometry and naming conventions.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the formula indicates there are 2 moles of Potassium Alum, while others argue that it represents only 1 mole of Potassium Alum, depending on how the formula is interpreted.
  • A participant clarifies that the '*' indicates that the 12 water molecules are associated with the 2 moles of Potassium Alum, suggesting that the entire structure is considered as 1 mole of Potassium Alum.
  • Another participant expresses confusion about how 2 moles of Aluminum can react with what is perceived as 1 mole of Potassium Alum, seeking clarification on the stoichiometric relationship.
  • It is noted that the definition of Potassium Alum can vary based on how the formula is presented, leading to different interpretations regarding the mole relationship between Aluminum and Potassium Alum.
  • One participant confirms that the formula is written with the 2 outside the entire structure, leading to the conclusion that 2 moles of Aluminum react with 2 moles of Potassium Alum, suggesting a 1:1 ratio.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the interpretation of the formula and the corresponding mole relationships, as multiple competing views remain regarding the definition of Potassium Alum and its stoichiometric implications.

Contextual Notes

The discussion highlights the importance of precise chemical notation and definitions, as different interpretations can lead to varying conclusions about mole relationships in chemical reactions.

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Hi guys,

I know the formula for Potassium Alum is:

2KAl(SO_{4})_{2} * 12H_{2}O

Now does this mean that there are 2 Moles of Potassium Alum or 24 moles of Potassium Alum if you include the 12 water molecules? I know when you calculate the molar mass of Potassium Alum, you need to add in the molar mass of the 12 water molecules.

Thanks
 
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It means there are 2 moles of potassium alum in that formula as written. The '*' just means that each molecule set 2KAl(SO_{4})_{2} is surrounded by 12 molecules of water. But if that is the exact formula for potassium alum then 2KAl(SO_{4})_{2} * 12H_{2}O is only 1 mole. There are 2 moles of potassium and 2 moles of aluminum, but that entire structure is only 1 mole of potassium alum.
 
Hi dmoravec, thanks for the reply. I am just confused on how there can be only 1 mole for that whole structure.

I just need help on converted moles of aluminum to moles of alum.

2K^+ + 2Al^+3 + 4SO_{4}^-2 + 12H_{2}O --> 2KAl(SO_{4})_{2} * H_{2}O

Now does this mean that 2 moles of Aluminum react with 2 moles of Potassium Alum or just 1 mole, as you mentioned above, of Postassium Alum?

Thanks again
 
well, its a bit nitpicky and just depends on naming but it could be either depending on how you define 1 molecule of potassium alum and how exactly the right side of the equation is written. If potassium alum is defined as 2KAl(SO_{4})_{2} * 12H_{2}O then it would be 2 moles of aluminum equating with 1 mole of potassium alum. If potassium alum is defined as KAl(SO_{4})_2*12H_{2}O then it would be 2 moles of aluminum equating with 2 moles of potassium alum.

(the difference lies in the formula above being (2KAl(SO_{4})_2*12H_{2}O) or
2(KAl(SO_{4})_2*12H_{2}O))
 
Thanks dmoravec...the formula is actually written as the latter, with the 2 on the outside of the entire formula, so it must be 2 moles of aluminum reacting with 2 moles of potassium alum, in other words a 1:1 ratio. Thanks again, it was a big help
 

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