Moment of Inertia and Frequency of Oscillation

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SUMMARY

The calculation of moment of inertia in relation to the frequency of oscillation requires knowledge of both the restoring force and the angular displacement. Specifically, when a body is hung on a pivot and displaced by a small angle θ, it undergoes simple harmonic motion. The relationship is defined by the equation τ = I d²θ/dt², where τ represents the torque due to gravity acting at the center of mass, and I is the moment of inertia. By applying the small angle approximation sin θ ≈ θ, one can derive the angular frequency ω, which is related to frequency f by the equation ω = 2πf.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Knowledge of torque and moment of inertia concepts
  • Familiarity with angular displacement and its approximations
  • Basic grasp of oscillation frequency calculations
NEXT STEPS
  • Study the derivation of the moment of inertia for various shapes
  • Learn about the principles of simple harmonic motion in detail
  • Explore the relationship between torque and angular acceleration
  • Investigate the effects of restoring forces in oscillatory systems
USEFUL FOR

Physics students, mechanical engineers, and anyone involved in the study of oscillatory motion and dynamics will benefit from this discussion.

UKDv12
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How do you calculate the moment of inertia given frequency of oscillation?
 
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You are going to need more than just the frequency. You will need to know the restoring force.

I think the problem you are describing is a body hung on a pivot through a point on it and the body is displaced by a small angle θ with gravity acting on the centre of mass to restore equilibrium. In the limit of small θ the body executes simple harmonic motion.

For angular displacements the equivalent of F=ma is τ = I d2θ /dt2 where τ is the torque about the pivot of gravity (mg) acting at the centre of mass and I is the moment of inertia about the pivot.

Put this together and use the approximation sin θ ≈ θ for small θ and as you would for a simple pendulum solve to find ω (= dθ/dt)

since ω (= 2 \pi f) you have solved the problem

Hope this makes sense and helps

regards

Sam
 
Last edited:

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