Moment of Inertia/Angular Speed/Torque

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The discussion focuses on calculating the change in angular speed of a construction made of two circular rings subjected to a tangential force. The moment of inertia for each ring was computed using the formula I = (1/2)M(R1^2 + R2^2), resulting in values of 1.3686e-4 kg*m^2 for Ring 1 and 0.003324 kg*m^2 for Ring 2. The total moment of inertia was found by summing the individual moments of inertia. The correct approach to find angular acceleration involved using torque, calculated as the product of the applied force and the outer radius. The final change in angular speed was determined to be approximately 157.80 rad/s after correcting the initial miscalculations.
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Homework Statement


A flat construction of two circular rings that have a common center and are held together by three rods of negligible mass. The construction, which is initially at rest, can rotate around the common center (like a merry-go-round) through which another rod of negligible mass extends. Mass 1 is 0.12 kg, its inside and outside radii are 0.016 m and 0.045 m, respectively. Mass 2 is 0.24 kg, its inside and outside radii are 0.090 m and 0.140 m, respectively. A tangential force of magnitude 13.0 N is applied to the outer edge of the outer ring for 0.300 s. What is the change in the angular speed of the construction during that time interval?


Homework Equations


I believe the following is the correct moment of inertia formula for this problem:

I = (1/2)M(R1^2 + R2^2)


The Attempt at a Solution


What I have done so far is calculate each ring's moment of inertia.

Ring 1:
I1 = (1/2)M(R1^2 + R2^2)
I1 = (1/2)(0.12 kg)((0.016 m)^2 + (0.045 m)^2)
I1 = 1.3686e-4 (kg*m^2)

Ring 2:
I2 = (1/2)M(R1^2 + R2^2)
I2 = (1/2)(0.24 kg)((0.090 m)^2 + (0.140 m)^2)
I2 = .003324 (kg*m^2)

This is as far as I have gotten and I am not even sure if the work I have done thus far is relevant. I am not sure what to do with the tangential force provided by the problem. I know F = ma, but I am not sure where that, or if it even does, fit in. Please help, this one has been stumping me for a while. Thanks for your time.
 
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The two rings are a blind. You can treat the construct as one assembly with a MoI given by the sum of the MoI of the two rings.

So the problem is just to calculate the angular acceleration caused by a tangential force.
Have a look here http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html and you'll see it's just like a = f/m.
 
Okay, so I used the formula from the reference you gave me, alpha = F/I:

alpha = (13 N)/(0.00346 kg*m^2)
alpha = 3757.225434 rad/s^2

also I know the equation for angular speed relative to angular acceleration:
w = alpha * time

so,
w = (3757.225434 rad/s^2)(0.300 s)
w = 1127.16763 rad/s

Unfortunately I made a mistake because that is wrong. I don't think I need to use one of the constant acceleration equations because the angular acceleration isn't constant. I thought I was on the right track. Thanks for your time.
 
Nevermind, I figured out where my error was. I don't know why I did this, but I set the torque to just the tangential force. Torque is defined as force * radius. Thus all I needed to do was to multiply the 13 N force in my problem by the outer radius since that is where the force is applied. My final answer came to 157.8034682 rad/s.

Thanks, Mentz114 for leading me in the right direction.
 

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