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- Thread starter Gauranga
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berkeman

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Welcome to the PF.

What is the context of the question? Where is this part used, and why do you need its moment of inertia?

What is your math and engineering background? Are you familiar with the basic equations for calculating the moment of inertia?

http://en.wikipedia.org/wiki/Moment_of_inertia

.

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berkeman

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Often for hollow things, you can subtract out the quantity for the inner hollow part from the overall solid part. If you can calculate the MofI for a solid torus, you can calculate it for a hollow one...

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if you do not find a formula, you may need to go back to the basics and calculate the moment of inertia yourself....

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Pyrrhus

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Torque is I* angular acceleration.

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Yes, u have to get time of acceleration to that speed. Also, is the acceleration uniform?

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I am all into it and it is the part of my last question which is proceeding further and further as i have lots to do about it.However thank.

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Yea. I understand now. Thanks.

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First of all i found the moment of inertia.Then i have the value of a stroke, from where i calculated the rpm.

Then by the formula 2.pi.rpm/60 ,i got the angular acceleration in rad/sec.So i devided the acceleration time by it and got the angular acceleration in rad/sec^2 .

I multiplied that with moment of inertia which was in kg m^2 and got a value in kg.m^2rad/ sec^2.

Where i think rad has no play.so the resulting unit will be Nm which is the right unit for torque.

Can somebody just have a look on the method and say me if i am right?

- #22

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Looks good. And you're correct about the units, as "rad" is considered unitless.

First of all i found the moment of inertia.Then i have the value of a stroke, from where i calculated the rpm.

Then by the formula 2.pi.rpm/60 ,i got the angular acceleration in rad/sec.So i devided the acceleration time by it and got the angular acceleration in rad/sec^2 .

I multiplied that with moment of inertia which was in kg m^2 and got a value in kg.m^2rad/ sec^2.

Where i think rad has no play.so the resulting unit will be Nm which is the right unit for torque.

Can somebody just have a look on the method and say me if i am right?

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Thanks........

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