Moment of Inertia - Non uniform density

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SUMMARY

The discussion focuses on calculating the moment of inertia for a non-uniform density rod, specifically a rod of length 3m with a density function of ρ(x) = (15 - 2x) kg/m. To find the moment of inertia about an axis perpendicular to the rod through end A, users are advised to use integration instead of summation. The kinetic energy of the rod when rotating at an angular velocity of 2 rad/s can also be derived from the moment of inertia. Additionally, the moment of inertia about an axis through the center of mass can be deduced using the results from the previous calculations.

PREREQUISITES
  • Understanding of moment of inertia and its calculation
  • Familiarity with integration techniques in physics
  • Knowledge of linear mass density concepts
  • Basic principles of rotational motion and kinetic energy
NEXT STEPS
  • Learn how to perform integration for calculating moment of inertia
  • Study the relationship between linear mass density and moment of inertia
  • Explore the concept of center of mass in non-uniform objects
  • Investigate the effects of angular velocity on kinetic energy in rotational systems
USEFUL FOR

Students preparing for physics exams, particularly those focusing on mechanics and rotational dynamics, as well as educators teaching concepts related to moment of inertia and non-uniform density materials.

JerS
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Homework Statement



Hey, need a quick bit of help, Maths Physics end of year exam and I can't find how to calculate the moment of inertia of a non uniform bod thin rod.

I'll post the question here for reference -

1. A rod AB of length 3m has non-uniform density x  15 − 2xkg/m where x measures
distance (in m) from the end A of the rod.
a. Find the moment of inertia of the rod about an axis perpendicular to the rod through the end
A.
b. Use your result to find the kinetic energy of the rod when it is rotating about the given axis
with angular velocity 2rad / s.
c. Deduce the moment of inertia of the rod about an axis parallel to the given axis but passing
through the centre of mass of the rod.
[Use the result in question 1 above for the location of the centre of mass.]

but I really just need the formula,

Thanks tons!



Homework Equations



I = Sigma m.r^2 ?



The Attempt at a Solution



Around 3 A4 pages of pointlessness
 
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JerS said:

Homework Statement



Hey, need a quick bit of help, Maths Physics end of year exam and I can't find how to calculate the moment of inertia of a non uniform bod thin rod.

I'll post the question here for reference -

1. A rod AB of length 3m has non-uniform density x  15 − 2xkg/m where x measures
distance (in m) from the end A of the rod.
a. Find the moment of inertia of the rod about an axis perpendicular to the rod through the end
A.
b. Use your result to find the kinetic energy of the rod when it is rotating about the given axis
with angular velocity 2rad / s.
c. Deduce the moment of inertia of the rod about an axis parallel to the given axis but passing
through the centre of mass of the rod.
[Use the result in question 1 above for the location of the centre of mass.]

but I really just need the formula,

Thanks tons!



Homework Equations



I = Sigma m.r^2 ?



The Attempt at a Solution



Around 3 A4 pages of pointlessness

Welcome to the PF. You will use an integration instead of the Sigma sum. Just break the rod up into little mass pieces dm, with a linear mass density, and a small length dx. Use the equation that you are given for the linear mass density (units are kg/m), and express the each little mass piece dm in terms of that density and the small length piece dx.

Then use the formula that you allude to with your "I = Sigma m.r^2", but use an integration over x, of dm*x^2. Does that help?
 

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