Moment of inertia of a solid sphere

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The discussion focuses on calculating the moment of inertia of a solid sphere about an axis through its center. The initial attempt incorrectly integrated using a uniform density approach without accounting for the varying distances of points in a spherical shell from the axis of rotation. The correct method involves using spherical shells, where the distance from the axis varies, leading to the proper setup of the integral. The final correct moment of inertia for a solid sphere is (2/5)MR^2, highlighting the importance of accurately considering the geometry of the problem. Understanding the integration method is crucial for obtaining the correct result.
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Homework Statement


Find the moment of inertia of a solid sphere of uniform mass density (like a billiard ball) about an axis through its center

Homework Equations


I = ∫rρdV

The Attempt at a Solution


I =ρ ∫r4πr2dr = ρ4π∫r4
Then I integrate this from 0 (the center) to R, so I = (ρ4π)*(R5/5)
And ρ = mv so ρ = M/(4/3)πR3 = 3M/4πR3. Put ρ into the equation for moment of inertia to get I = 3MR2/5.

My book tells me the answer is (2/5)MR^2. Where did I go wrong?
 
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henry3369 said:

Homework Statement


Find the moment of inertia of a solid sphere of uniform mass density (like a billiard ball) about an axis through its center

Homework Equations


I = ∫rρdV

The Attempt at a Solution


I =ρ ∫r4πr2dr = ρ4π∫r4
Then I integrate this from 0 (the center) to R, so I = (ρ4π)*(R5/5)
And ρ = mv so ρ = M/(4/3)πR3 = 3M/4πR3. Put ρ into the equation for moment of inertia to get I = 3MR2/5.

My book tells me the answer is (2/5)MR^2. Where did I go wrong?

Can you explain how you are setting up the integral? What shape are you integrating from 0 to R?
 
PeroK said:
Can you explain how you are setting up the integral? What shape are you integrating from 0 to R?
The surface area of a spherical shell from the center of the sphere to the outer shell of radius R.
 
I figured it out. If I use spherical shells, the points from the shell aren't all the same distance form the axis of rotation. I was thinking about the distance from the center.
 
henry3369 said:
I figured it out. If I use spherical shells, the points from the shell aren't all the same distance form the axis of rotation. I was thinking about the distance from the center.
Exactly!
 
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