Moment of inertia of a system of masses

AI Thread Summary
The moment of inertia for a system of two masses (3.0 kg and 5.0 kg) connected by a negligible mass rod is being calculated, with initial attempts yielding incorrect results. The correct approach involves using the equation for the center of mass, expressed as (m1+m2)R = m1r1 + m2r2, to determine the system's balance point. Once the center of mass is established, the moment of inertia can be calculated by summing the products of mass and the square of their distances from the center of mass. Various methods for finding the center of mass, including algebraic calculations and physical suspension techniques, are discussed. The conversation emphasizes the importance of correctly identifying the center of mass before calculating the moment of inertia.
Pablo
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Homework Statement



The moment of inertia about an axis through the center of mass of a system consisting of two masses 3.0 and 5.0 kg connected by a rod of negligible mass 0.8m long is

Homework Equations


[/B]
I = I1 + I2

The Attempt at a Solution



I added all the moments of inertia of the system about the middle (0.4m)

I = m1R^2 + m2R^2 = (m1 + m2) * R^2 = (3 + 5) * 0.4^2 = 1.28

However, 1.28 is not the right answers. Does anyone know where I went wrong?
 
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I am no expert but my syllabus is same
I am trying for practice
(m1+m2)R=m1r1+m2r2
8(R)=3(0)+5(0.8)
8R=4
R=1/2
Mment of inertia=MR^2
=8 1/4
=2 Kg m^2
is this correct please tell me
 
Suyash Singh said:
I am no expert but my syllabus is same
I am trying for practice
(m1+m2)R=m1r1+m2r2
8(R)=3(0)+5(0.8)
8R=4
R=1/2
Mment of inertia=MR^2
=8 1/4
=2 Kg m^2
is this correct please tell me
Could you explain what this equation means:

(m1+m2)R=m1r1+m2r2
 
Pablo said:
the center of mass of a system

Pablo said:
moments of inertia of the system about the middle (0.4m)
Is that the centre of mass?
 
Pablo said:
Could you explain what this equation means:

(m1+m2)R=m1r1+m2r2
Is my answer correct?
Learn this equation which i have given
(m1+m2)R=m1r1+m2r2
where m1 and m2 are the given masses
r1 and r2 are their respective positions
R is the position of center of mass
 
The first move is to establish the location of the center of mass. It is the balance point where the torques due to the different weights are equal and opposite. Then the moment of inertia can be calculated as the sum of the m r^2 terms.
 
Dr Dr news said:
The first move is to establish the location of the center of mass. It is the balance point where the torques due to the different weights are equal and opposite.
Are torques and weights needed to find the center of mass of this and other systems?
 
Another way to find the center of mass is to suspend the body and a plumb bob from the same suspension point and repeat using a different point of suspension. Where the two plumb lines cross is the location of the c.m.
 
Dr Dr news said:
Another way to find the center of mass is to suspend the body and a plumb bob from the same suspension point and repeat using a different point of suspension. Where the two plumb lines cross is the location of the c.m.
Isn't there a mathematical way to find the CM using algebra?
 
  • #10
Certainly. If you Google center of mass you will find several equations.
 
  • #11
Dr Dr news said:
Certainly. If you Google center of mass you will find several equations.
I will keep that under advisement. Thanks.
 
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