Moment of Inertia Using Parallel Axis Theorem

Click For Summary
SUMMARY

The moment of inertia of a cube about an axis along one face, denoted as Pface, can be calculated using the parallel axis theorem. Given that the moment of inertia about an axis through the center and the center of two opposing faces is PCM = (1/6)mQ^2, the formula Pface = PCM + md^2 is applied with d = (1/2)Q. The final result for Pface is (5/12)mQ^2, confirming the calculations are accurate with the correct distance d = Q/2.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with the parallel axis theorem
  • Basic algebra for manipulating equations
  • Knowledge of cube geometry and properties
NEXT STEPS
  • Study the derivation of the parallel axis theorem in detail
  • Explore applications of moment of inertia in rotational dynamics
  • Learn about different shapes and their moments of inertia
  • Investigate the impact of mass distribution on moment of inertia
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational motion, as well as educators teaching concepts related to moment of inertia and the parallel axis theorem.

woaini
Messages
58
Reaction score
0

Homework Statement



VlBTZHQ.png


Q is the edge length of the cube. The moment of inertia of the cube about an axis passing through its center and the center of two opposing faces is (1/6)mQ^2 (PCM in the diagram). Use the parallel axis theorem to find the moment of inertia if the axis is along one face of the cube (Pface).

PCM=(1/6)mQ^2
Pface=?
d=?

Homework Equations



Pface = PCM+md^2

The Attempt at a Solution



d=(1/2)Q^2

Pface=\frac{mQ^2}{6}+\frac{mQ^2}{4}

Pface=\frac{5mQ^2}{12}
 
Physics news on Phys.org
woaini said:

Homework Statement



VlBTZHQ.png


Q is the edge length of the cube. The moment of inertia of the cube about an axis passing through its center and the center of two opposing faces is (1/6)mQ^2 (PCM in the diagram). Use the parallel axis theorem to find the moment of inertia if the axis is along one face of the cube (Pface).

PCM=(1/6)mQ^2
Pface=?
d=?

Homework Equations



Pface = PCM+md^2

The Attempt at a Solution



d=(1/2)Q^2

Pface=\frac{mQ^2}{6}+\frac{mQ^2}{4}

Pface=\frac{5mQ^2}{12}

Correct...except d = Q/2
 
Last edited:

Similar threads

  • · Replies 28 ·
Replies
28
Views
2K
Replies
2
Views
2K
Replies
11
Views
4K
Replies
25
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 40 ·
2
Replies
40
Views
6K