Moments of Inertia of two particles

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SUMMARY

The moment of inertia of a system consisting of two particles and a uniform circular disk must be calculated correctly about a specified axis. The moment of inertia of the disk is incorrectly stated as 0.5ma²; the correct approach involves using the parallel axis theorem. The moment of inertia for the particles at points Q and P is calculated as m(b+a)² and m(a-b)², respectively. To find the total moment of inertia about point A, one must first determine the moment of inertia about the center of mass and then apply the parallel axis theorem.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with the parallel axis theorem
  • Knowledge of rotational dynamics
  • Ability to apply basic physics equations related to mass and distance
NEXT STEPS
  • Review the parallel axis theorem in detail
  • Learn how to calculate the moment of inertia for composite systems
  • Study the derivation of moment of inertia for a uniform circular disk
  • Practice problems involving multiple masses and axes of rotation
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Students studying physics, particularly those focusing on rotational dynamics and moment of inertia calculations, as well as educators seeking to clarify these concepts for their students.

Spaceflea
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Homework Statement



Two particles, each of mass m, are attached one to each end of a diameter PQ of a uniform circular disk, of mass 4m, radius a with its centre at O. The system is free to rotate about a horizontal axis through A, a point on PQ such that OA = b as indicated in the diagram below. The system is released from rest when PQ is horizontal.[/B]
Determine the Moment of Inertia of the system about the axis A, in terms of integer constants, a , b and m.

Homework Equations


I=ma^2
parallel axis equation I=Icentre of mass + md^2

The Attempt at a Solution


I have determined the moment of inertia of the disc to be 0.5ma^2.
I have determined the moment of inertia of Q to be m(b+a)^2.
I have determined the moment of inertia of P to be m(a-b)^2.
Therefore I should just add these three numbers together to make a total moment of inertia, but this answer is marked wrong (it is marked by a computer programme). Where am I going wrong in my method? Thanks.
 
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Spaceflea said:
I have determined the moment of inertia of the disc to be 0.5ma^2.
That's the generic formula for a circular disk about its center. You'll have to modify it.

Spaceflea said:
I have determined the moment of inertia of Q to be m(b+a)^2.
I have determined the moment of inertia of P to be m(a-b)^2.
These are OK.

Spaceflea said:
Therefore I should just add these three numbers together to make a total moment of inertia, but this answer is marked wrong (it is marked by a computer programme). Where am I going wrong in my method?
Your expression for the moment of inertia of the disk is incorrect: You have the wrong mass and the wrong axis.

Correct that, and your method should work fine.

Another approach would be to find the moment of inertia of the entire system about its center of mass, then use the parallel axis theorem. Do it both ways and compare!
 
Thanks so much for the reply! But I am confused over which axis and mass I should use instead. Obviously not point A...
 
Spaceflea said:
But I am confused over which axis and mass I should use instead. Obviously not point A...
I assume you are talking about the disk? What's the mass of the disk? You need its moment of inertia about point A, but don't start there. Start with the moment of inertia about the center of mass and use the parallel axis theorem.
 

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