Moments of Inertia of two particles

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Homework Help Overview

The problem involves calculating the moment of inertia of a system consisting of two particles and a uniform circular disk. The particles are attached to the ends of a diameter of the disk, and the system rotates about a horizontal axis through a point on the diameter.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the moment of inertia of the disk and the particles, questioning the correct mass and axis to use for calculations. There is mention of using the parallel axis theorem and comparing different approaches.

Discussion Status

Some participants have provided guidance on correcting the moment of inertia of the disk and suggested starting from the center of mass. There is an ongoing exploration of the correct parameters to use in the calculations, but no consensus has been reached on the specific method to apply.

Contextual Notes

Participants express confusion regarding the appropriate axis and mass for the calculations, indicating potential misunderstandings about the setup of the problem. The original poster's attempts have been marked incorrect by a computer program, prompting further inquiry into the method used.

Spaceflea
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Homework Statement



Two particles, each of mass m, are attached one to each end of a diameter PQ of a uniform circular disk, of mass 4m, radius a with its centre at O. The system is free to rotate about a horizontal axis through A, a point on PQ such that OA = b as indicated in the diagram below. The system is released from rest when PQ is horizontal.[/B]
Determine the Moment of Inertia of the system about the axis A, in terms of integer constants, a , b and m.

Homework Equations


I=ma^2
parallel axis equation I=Icentre of mass + md^2

The Attempt at a Solution


I have determined the moment of inertia of the disc to be 0.5ma^2.
I have determined the moment of inertia of Q to be m(b+a)^2.
I have determined the moment of inertia of P to be m(a-b)^2.
Therefore I should just add these three numbers together to make a total moment of inertia, but this answer is marked wrong (it is marked by a computer programme). Where am I going wrong in my method? Thanks.
 
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Spaceflea said:
I have determined the moment of inertia of the disc to be 0.5ma^2.
That's the generic formula for a circular disk about its center. You'll have to modify it.

Spaceflea said:
I have determined the moment of inertia of Q to be m(b+a)^2.
I have determined the moment of inertia of P to be m(a-b)^2.
These are OK.

Spaceflea said:
Therefore I should just add these three numbers together to make a total moment of inertia, but this answer is marked wrong (it is marked by a computer programme). Where am I going wrong in my method?
Your expression for the moment of inertia of the disk is incorrect: You have the wrong mass and the wrong axis.

Correct that, and your method should work fine.

Another approach would be to find the moment of inertia of the entire system about its center of mass, then use the parallel axis theorem. Do it both ways and compare!
 
Thanks so much for the reply! But I am confused over which axis and mass I should use instead. Obviously not point A...
 
Spaceflea said:
But I am confused over which axis and mass I should use instead. Obviously not point A...
I assume you are talking about the disk? What's the mass of the disk? You need its moment of inertia about point A, but don't start there. Start with the moment of inertia about the center of mass and use the parallel axis theorem.
 

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