Momentum change after explosion

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The discussion centers on the mechanics of momentum change after an explosion involving a trolley and a spring. It is clarified that an external force, in this case, the spring, exerts an impulse on the trolley, resulting in a change in momentum despite the trolley providing the spring's energy. The key point is that the trolley's momentum can be reversed due to this external force. Additionally, a supplementary question about finding a shorter solution to a problem is addressed, with participants agreeing that the current solution is adequate. Overall, the conversation emphasizes the role of external forces in momentum changes.
coconut62
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1. Please refer to the first image, the yellow star question. No answer is provided at the back so I'm not very sure whether my reasoning is correct. Is it because the spring exerted an impulse on that trolley, causing its momentum to change? But all the spring's energy was provided by the trolley, how can it increase the trolley's momentum when it does not have any initial energy itself?

2. (This is a supplementary question :blushing:) The yellow star question in image 2. My workings in image 3. Is there any shorter solution?
 

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where is the image?
 
There.

Error just now, heh heh.
 
coconut62 said:
1. Please refer to the first image, the yellow star question. No answer is provided at the back so I'm not very sure whether my reasoning is correct. Is it because the spring exerted an impulse on that trolley, causing its momentum to change? But all the spring's energy was provided by the trolley, how can it increase the trolley's momentum when it does not have any initial energy itself?
The relevant fact is that an outside force acted on the trolleys. That produces a change in momentum. The fact that the trolley just bounces off the spring with the same energy does not change the fact that its momentum was reversed.

2. (This is a supplementary question :blushing:) The yellow star question in image 2. My workings in image 3. Is there any shorter solution?
Your solution looks good. I don't think there's a shorter way. I would have done the same.
 
Thank you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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