Momentum change by increasing time of impact

Click For Summary
SUMMARY

The discussion centers on the relationship between momentum, force, and time during collisions, specifically addressing how increasing the time of impact reduces the force exerted. It is established that in elastic collisions, the mass of the objects involved significantly influences momentum transfer. The conversation clarifies that momentum is a vector quantity, and while two equal masses colliding can result in a net momentum of zero, each object experiences a change in momentum. The principles of impulse and momentum conservation are emphasized, particularly in the context of varying mass interactions.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of momentum and impulse
  • Knowledge of elastic and inelastic collisions
  • Basic grasp of vector quantities in physics
NEXT STEPS
  • Study the principles of elastic and inelastic collisions in detail
  • Learn about momentum conservation in multi-body systems
  • Explore the mathematical formulation of impulse and its applications
  • Investigate the effects of mass and velocity on collision outcomes
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of collisions and momentum transfer in physical systems.

beginner16
Messages
51
Reaction score
0
hi, thank you for helping

For same momentum change if we increase the time of impact by factor ten then force is smaller by factor ten.

But why is that? I mean why doesn't a moving object at point of impact give away all of its momentum at the instant it hits something,no matter if that something is a wall or a ball or a piece of paper?


when two objects collide any combination of force and time could be used to produce certain impulse. What are the parameters that decide ( for specific impulse ) the amount of force two object colliding will exert on each other and the amount of time collision will last?



If two balls with same mass and speed go towards each other then momentum is zero. When they colide they both lose momentum, so how can they claim if one object loses momentum then the other object gains momentum?
I see that being true if both objects are moving in same direction or one is still. In that case one object would loose while other would gain momentum

cheers
 
Physics news on Phys.org
This should help explain it.
http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html#c1, or more specifically to the question
http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html#c2

Basically a force, F, is produces a change in momentum dp/dt, and assuming that mass is constant dp/dt = m dv/dt = m a where a is acceleration, which after all is a change in velocity with respect to time.

Increasing the time over which the force is applied simply reduces the acceleration, so the time rate of change of velocity (and momentum) decreases.

The masses of the bodies involved affect the rate of transfer of momentum, as well as the stiffness of the materials. But assuming purely elastic collisions (i.e. no deformation of the mass) the mass of each object involved is main factor.

If two balls with same mass and speed go towards each other then momentum is zero. When they colide they both lose momentum, so how can they claim if one object loses momentum then the other object gains momentum?
Well momentum is a vector (velocity is a vector). Depending on the coordinate system, one ball has - momentum and one has + momentum. The + momentum decreases to zero, the - momentum increases to zero. However in both cases, the magnitude of the momentum (and speed) decrease from some + value to zero.
 
The masses of the bodies involved affect the rate of transfer of momentum, as well as the stiffness of the materials. But assuming purely elastic collisions (i.e. no deformation of the mass) the mass of each object involved is main factor.

So for an object to give away all of its momentum in a moment it would have to collide with an object with large mass?
It makes sense on some intuitive level, but is there way to explain why it doesn't give away all of its momentum in a brief moment if it collides with a piece of paper or something with small mass?


However in both cases, the magnitude of the momentum (and speed) decrease from some + value to zero.

I'm not shure what you mean by that. Net momentum is same after collision as it was before the collision
 
beginner16 said:
So for an object to give away all of its momentum in a moment it would have to collide with an object with large mass?
Not quite. Assuming an elastic collision, a small mass hitting an extremely large mass will transfer very little momentum, but rather will reverse direction. The maximum transfer of momentum and kinetic energy occur when one mass hits an equal mass.

A large mass hitting a light mass keeps most of its momentum, with little or no change in direction. A light mass hitting a large mass will ricochet or recoil, retaining most of its momentum, but changing direction.

beginner16 said:
I'm not shure what you mean by that. Net momentum is same after collision as it was before the collision
The net momentum is zero before and after, but each mass has a positive 'magnitude' of momentum, p, where p = mv, where v is the speed. Speed is always positive, but velocity, which has direction can be - or +.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
4
Views
1K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K