How Does Mass Affect Velocity in an Elastic Collision?

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The discussion centers on the elastic collision between two pucks on an air-hockey table, focusing on the effects of mass and velocity. Puck A, with a mass of 0.023 kg and a velocity of +5.5 m/s, collides with puck B, which has a mass of 0.048 kg and is initially at rest. Participants are troubleshooting their calculations for momentum conservation in both the x and y directions, noting discrepancies in their equations. A key point of confusion arises regarding the correct application of initial and final velocities in the momentum equations. The conversation emphasizes the importance of correctly applying conservation laws and clarifying variable definitions in collision problems.
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The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.023 kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.048 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing.

http://www.webassign.net/CJ/07_32.gif

(Puck A is 65 degrees north of east, puck B is 37 degrees south of east.)


I used MaVa = MaVa(cos 65) + MbVb(cos 37), which gives me
.1265 = .0097202Va + .03833Vb. Since the total momentum in the Y direction was zero, I also used
Va(sin 65) = Vb(sin 37)
Va = .6640Vb or Vb = 1.506Va.

Every time I plug in those numbers I get a wrong value! Am I missing some important concept, or am I just making an algebraic error?
 
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> I used MaVa = MaVa(cos 65) + MbVb(cos 37)

You Va on RHS should be different from initial Va on LHS.
 
Aah, thanks for pointing that out. I had the Va on the LHS as Vo when I did the problem, though, so it didn't change my answer.
 
> Va(sin 65) = Vb(sin 37)

Why? It should be MaVasin 65 = MbVbsin 37.
 
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