Momentum of electron from total energy of electron

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Homework Help Overview

The discussion revolves around calculating the momentum of an electron given its total energy, which is five times its rest energy. The context involves relativistic physics, specifically the relationship between energy, momentum, and velocity of particles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the relativistic energy equation to find the velocity of the electron and then attempt to derive momentum from that. There are questions about the correct method to convert energy and velocity into momentum, as well as concerns about unit conversions.

Discussion Status

Some participants are exploring different interpretations of the equations involved and questioning the steps taken to derive momentum. Guidance has been offered regarding the definition of relativistic momentum and how to relate it to the energy and velocity already calculated.

Contextual Notes

There is uncertainty regarding the conversion of units from kg*m/s to MeV/c, and participants are navigating the implications of using relativistic equations in their calculations.

umwolv16
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Homework Statement



An electron has a total energy equal to five times its rest energy(0.511MeV).

--What is its momentum (in MeV/c)?


Homework Equations



E(total) = [mass(electron)*c^2]/[sq. root of (1- velocity^2/c^2)]
----I converted 2.555MeV (total energy) to 4.088e-13 J and plugged that in for E(total) to solve for velocity

The Attempt at a Solution



I used the EQN above to solve for velocity of the electron [in terms of c(speed of light)].
I then divided the total energy (2.555MeV) by this velocity (which I got to be 0.979680884c) and got the answer 2.61MeV/c. When I submit it, it says I'm within 10%, but I didn't round any numbers until the can't see what I did wrong...
 
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umwolv16 said:

Homework Statement



An electron has a total energy equal to five times its rest energy(0.511MeV).

--What is its momentum (in MeV/c)?


Homework Equations



E(total) = [mass(electron)*c^2]/[sq. root of (1- velocity^2/c^2)]
----I converted 2.555MeV (total energy) to 4.088e-13 J and plugged that in for E(total) to solve for velocity

The Attempt at a Solution



I used the EQN above to solve for velocity of the electron [in terms of c(speed of light)].
I then divided the total energy (2.555MeV) by this velocity

I don't believe that is correct; if you look at the equation you are using I think you'll find that you don't divide the energy by velocity to get momentum. What do you get?
 
I thought I solved for momentum because I found the velocity by the EQN i gave and I know the mass of an electron, but the units weren't right. I didn't know how to convert kg*m/s to MeV/c. I had energy in MeV and found my velocity in terms of c, so I couldn't think of anything else to do, but divide them. I feel like I'm using the right EQN, but I'm not sure how to derive my answer
 
umwolv16 said:
I thought I solved for momentum because I found the velocity by the EQN i gave and I know the mass of an electron, but the units weren't right. I didn't know how to convert kg*m/s to MeV/c. I had energy in MeV and found my velocity in terms of c, so I couldn't think of anything else to do, but divide them. I feel like I'm using the right EQN, but I'm not sure how to derive my answer

I think what you are missing is the definition of the relativistic momentum:

momentum =(gamma) m v

Since you have already done the work to find v, you could actually just plug that in and solve it. However, to get the equation related to what you have already done, note that:

momentum = (gamma) m v
energy = (gamma) m c^2

putting these together gives:

(v / c) = p c / E

and since you already have E in MeV and v in terms of c, you can get momentum directly.
 

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