Momentum of electron from total energy of electron

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SUMMARY

An electron with a total energy of 2.555 MeV, which is five times its rest energy of 0.511 MeV, can be analyzed using relativistic equations. The momentum of the electron can be calculated using the formula for relativistic momentum: momentum = (gamma) m v, where gamma is the Lorentz factor. The discussion highlights the importance of correctly relating energy and momentum, emphasizing that dividing energy by velocity does not yield the correct momentum. Instead, using the relationship (v / c) = p c / E allows for direct calculation of momentum in MeV/c.

PREREQUISITES
  • Understanding of relativistic physics concepts
  • Familiarity with the Lorentz factor (gamma)
  • Knowledge of energy-momentum relationships
  • Basic skills in unit conversion between MeV and MeV/c
NEXT STEPS
  • Study the derivation of the Lorentz factor (gamma) in special relativity
  • Learn how to convert between different units of momentum, specifically kg*m/s to MeV/c
  • Explore the implications of relativistic effects on particle momentum and energy
  • Investigate additional examples of relativistic momentum calculations
USEFUL FOR

Physics students, educators, and anyone interested in understanding relativistic mechanics and particle physics will benefit from this discussion.

umwolv16
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Homework Statement



An electron has a total energy equal to five times its rest energy(0.511MeV).

--What is its momentum (in MeV/c)?


Homework Equations



E(total) = [mass(electron)*c^2]/[sq. root of (1- velocity^2/c^2)]
----I converted 2.555MeV (total energy) to 4.088e-13 J and plugged that in for E(total) to solve for velocity

The Attempt at a Solution



I used the EQN above to solve for velocity of the electron [in terms of c(speed of light)].
I then divided the total energy (2.555MeV) by this velocity (which I got to be 0.979680884c) and got the answer 2.61MeV/c. When I submit it, it says I'm within 10%, but I didn't round any numbers until the can't see what I did wrong...
 
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umwolv16 said:

Homework Statement



An electron has a total energy equal to five times its rest energy(0.511MeV).

--What is its momentum (in MeV/c)?


Homework Equations



E(total) = [mass(electron)*c^2]/[sq. root of (1- velocity^2/c^2)]
----I converted 2.555MeV (total energy) to 4.088e-13 J and plugged that in for E(total) to solve for velocity

The Attempt at a Solution



I used the EQN above to solve for velocity of the electron [in terms of c(speed of light)].
I then divided the total energy (2.555MeV) by this velocity

I don't believe that is correct; if you look at the equation you are using I think you'll find that you don't divide the energy by velocity to get momentum. What do you get?
 
I thought I solved for momentum because I found the velocity by the EQN i gave and I know the mass of an electron, but the units weren't right. I didn't know how to convert kg*m/s to MeV/c. I had energy in MeV and found my velocity in terms of c, so I couldn't think of anything else to do, but divide them. I feel like I'm using the right EQN, but I'm not sure how to derive my answer
 
umwolv16 said:
I thought I solved for momentum because I found the velocity by the EQN i gave and I know the mass of an electron, but the units weren't right. I didn't know how to convert kg*m/s to MeV/c. I had energy in MeV and found my velocity in terms of c, so I couldn't think of anything else to do, but divide them. I feel like I'm using the right EQN, but I'm not sure how to derive my answer

I think what you are missing is the definition of the relativistic momentum:

momentum =(gamma) m v

Since you have already done the work to find v, you could actually just plug that in and solve it. However, to get the equation related to what you have already done, note that:

momentum = (gamma) m v
energy = (gamma) m c^2

putting these together gives:

(v / c) = p c / E

and since you already have E in MeV and v in terms of c, you can get momentum directly.
 

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