What is the momentum of an object on an incline?

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SUMMARY

The momentum of an object on an incline can be calculated using the formula p=mv, where p represents momentum, m is mass, and v is velocity. In this discussion, a 5 kg box moving at a constant rate of 2 m/s results in a momentum of 10 kg-m/s. The question regarding the rate of change in momentum requires a different approach, emphasizing the distinction between magnitude and rate of change. The correct answer for the magnitude of the momentum is 10 kg-m/s.

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Homework Statement



A 20-Newton force pulling an object up a hill at a constant rate of 2 m/s. The diagram shows a box that is 5 kg on an incline that is 30 m long and 10 m high.

the answers are
1) 0 kg-m/s
2) 10 kg-m/s
3) 100 kg-m/s
4) 600 kg-m/s

The equation for momentum is p=mv

Homework Equations





The Attempt at a Solution



so wouldn't i just do
(5 Kg)(2 m/s)= 10 kg-m/s
 
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yes, if the question is "what is the magnitude of the momentum"
... but for "what is the rate of change in momentum", the answer is different .
 
yes it was what is the magnitude of the momentum?
thank you :)
 

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