Momentum problem with collision

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SUMMARY

The forum discussion centers on solving a physics problem involving an elastic collision between a cue ball and an eight ball, both of equal mass. The cue ball initially moves at 3.7 m/s and after the collision, its speed is reduced to 2.1 m/s at an unknown angle, theta. Participants emphasize the importance of using both conservation of momentum and conservation of kinetic energy to find the eight ball's speed post-collision, ultimately determining that the speed is 3.04 m/s. The discussion highlights the relevance of the line of collision (LOC) and the coefficient of restitution (e), although the latter is not necessary for perfectly elastic collisions.

PREREQUISITES
  • Understanding of elastic collisions in physics
  • Familiarity with conservation of momentum and kinetic energy principles
  • Knowledge of vector components and their application in collision problems
  • Basic grasp of the coefficient of restitution (e) and line of collision (LOC)
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  • Study the principles of conservation of momentum in elastic collisions
  • Learn about the coefficient of restitution and its implications in collision problems
  • Explore vector decomposition in two-dimensional motion
  • Practice solving collision problems using both energy and momentum conservation
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Students preparing for physics exams, particularly those studying mechanics and collision dynamics, as well as educators looking for practical examples of elastic collisions.

  • #31
I would say that this collision is to be modeled as a perfectly elastic collision, and so you can use conservation of kinetic energy as well as conservation of momentum.

(This also means you don't need to worry about the coefficient of restitution, which I gather you haven't been taught).
 
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  • #32
if i use conservation of energy why do i need to use conservation of momentum? I know that i should use both but:
before collision: all kinetic energy
after:all kinetic
there's no friction and everything is perfect so if i set the kinetic energy from before equal to after I would just have one unknown(the answer) to solve.
1/2mv^2=1/2mv^2+1/2mv^2
basically the 1/2 and mass all cancel
so:
3.7^2=2.1^2+V^2
V=3.04
this definitely doesn't seem right...
 
  • #33
yeah i tried what was above and it was right... w/o any momentum...strange
 
  • #34
hey, check ur gmail inbox
 

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