Momentum Qs: Find Girl & Skateboard Velocity After Jump

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SUMMARY

The discussion focuses on a physics problem involving momentum conservation, where a girl of mass 48 kg jumps onto a stationary skateboard weighing 2.0 kg. The girl’s initial horizontal velocity is 4.0 m/s. After she lands on the skateboard, the combined system's velocity is calculated to be 3.84 m/s. When she jumps off, she retains this velocity, which is also the skateboard's velocity at that moment, confirming the conservation of momentum principle.

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Homework Statement


A girl of mass 48kg runs toward her sationary 2.0kg skateboard and jumps on. The horizontal velocity of the girl just before she makes contact with the skateboard is 4.0m/s to the right. Disregard the effects of friction.
a)Determine the velocity of the girl after she has landed on the skateboard.
b)The girl then travels at this speed for a short time before jumping off, still traveling at the same speed as the skateboard. What is the velocity of the skateboard after she jumps off.


Homework Equations



p0=pf
(m1)(v01) + (m2)(v01) = (m1)(vf1) + (m2)(vf2)

The Attempt at a Solution


ok for b:
48kg * 4.0m/s = 50kg(v2)----> is this ok to consider skateboard and girl one
v2 =3.84m/s

ok for c) since she jumps off and has the same velocity, that means the skateboard will also have the same velocity
 
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crosbykins said:
48kg * 4.0m/s = 50kg(v2)----> is this ok to consider skateboard and girl one
v2 =3.84m/s
It's ok to to consider girl and skateboard as one if they have the same velocity, which
they have. The answer is correct
ok for c) since she jumps off and has the same velocity, that means the skateboard will also have the same velocity
[/QUOTE]
This is OK as well.
 

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