Vf = 0.88 m/s Solving Momentum Question: 82kg Girl & 46kg Boy on Skateboard

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Homework Help Overview

The problem involves a scenario where a girl on a skateboard is joined by a boy, and the goal is to determine the final speed of the skateboard after the boy jumps on. The context is centered around the conservation of momentum in a physics setting.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the conservation of momentum principle, with initial and final momentum equations being set up. There are questions about the correctness of calculated speeds and interpretations of the problem setup.

Discussion Status

Some participants have provided calculations and expressed uncertainty about the results. There is a recognition of potential discrepancies in the expected answers, with suggestions to verify the calculations and await further confirmation from knowledgeable peers.

Contextual Notes

There is mention of a possible error in the textbook regarding the expected final speed, and participants are considering whether all aspects of the problem have been addressed.

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Homework Statement


A 82kg girl is coasting along the floor on a large 2.0kg skateboard. If she is moving 1.8 m/s when a 46kg boy jumps on to the same skateboard, what is the speed of the skateboard immediately after the boy jumps on it?


Homework Equations



Sum of Initial Momentum = Sum of Final Momentum

The Attempt at a Solution



This question looked pretty easy.. but I am sure I am doing something wrong... here's what I did so far:
(84kg)(1.8m/s) + (130kg)(0m/s) = (84kg + 130kg)Vf
 
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Sorry.. forgot the last part..
I got vf=0.7065m/s

Im not sure if this is right or not.. it SEEMS like an okay speed.. but I havn't done this type of question before.. so just want to be sure. Thanks!
 
niki4d said:
(84kg)(1.8m/s) + (130kg)(0m/s) = (84kg + 130kg)Vf


You should only be looking at the initial and final momentums of the skateboard (and what ever is on it).

So it starts off with a total mass of 84 kg, going at 1.8 m/s. At the end, It has the mass of a 46 kg boy, so the total mass is 130 kg, and v_1 m/s is what we are trying to find. Equating both sides and making v_1 the subject;

84 kg \cdot 1.8 ms^{-1} = 130 kg \cdot v_1 ms^{-1}

v_1 = \frac{84 \cdot 1.8}{130}

I can already tell that's larger than one, so recheck your answer =]
 
Hmm.. that makes sense.. but the answer to that would be 1.163m/s. The answer is 0.97m/s. I don't know how to get to that..
 
Last edited:
Well, That is somewhat odd...I think it's an error in the textbook, but it has been a while since I've studied Physics so I recommend you wait for someone who has more knowledge in this area to confirm.
 
unless there are something else in the problem we have not addressed, otherwise I believe Gib Z's correct.
 
Yeah.. more than likely it is.. thanks for the help!
 

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