Separating kinetic energies of two masses in elastic collision

[Clara Chung]

Homework Statement

Homework Equations

The Attempt at a Solution

How do I calculate part d?
I know that (m₂-m₁)v₀ = m₂v₂+m₁v₁
where v₀ = root (2gh), v1 and v2 are the new velocity of the masses
(m₂+m₁)v₀² = m₂v₂² + m₁v₁²
I also know that v₂-v₁=2v₀
but how do I separate the KE of mass 2?

 

[PeroK]

Homework Statement

View attachment 223719

Homework Equations

The Attempt at a Solution

How do I calculate part d?
I know that (m₂-m₁)v₀ = m₂v₂+m₁v₁
where v₀ = root (2gh), v1 and v2 are the new velocity of the masses
(m₂+m₁)v₀² = m₂v₂² + m₁v₁²
I also know that v₂-v₁=2v₀
but how do I separate the KE of mass 2?

It's $m_1$ that is the upper ball. Can you solve the equations to find $v_1$?

 

[Clara Chung]

It's $m_1$ that is the upper ball. Can you solve the equations to find $v_1$?

I got a very strange answer...
v₂-v₁=2v₀ ...(1)
(m₂-m₁)v₀ = m₂v₂+m₁v₁...(2)
After substitution I get -v₀=v₁...