Momentum. resulting velocity. Rocket

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Homework Help Overview

The problem involves calculating the resulting velocity of an astronaut and equipment after firing a rocket backpack in a weightless environment. The context is centered around the principles of momentum and force applied over time.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts various formulas related to momentum and force but expresses difficulty in finding a relevant answer. Some participants suggest focusing on the effects of the rocket's force on the astronaut's momentum.

Discussion Status

Participants are exploring the relationship between force, time, and momentum. One participant has provided a calculation for the change in momentum and derived a velocity, while another has affirmed the approach taken. There is an ongoing examination of the reasoning behind the calculations.

Contextual Notes

The original poster indicates uncertainty about the starting point for solving the problem, and there may be assumptions regarding the application of formulas and the interpretation of the rocket's effect.

rtamplain
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[SOLVED] Momentum. resulting velocity. Rocket

Homework Statement



On earth, an astronaut and equipment weigh 1,960.0 N. While weightless in space, the astronaut fires a 100 N rocket backpack for 2.0 s. What is the resulting velocity of the astronaut and equipment?

I have to be missing something. I tried using every formula given to me in class and I cannot get anywhere. Please help. Thanks.

Homework Equations



p=mv
Ft= (mf)(vf)-(mi)(vi)
Ft=ma+v(difference of m/t)
m1v1=m2v2

The Attempt at a Solution


I tried a few and can't get a relevant answer. I really do not know where to begin with the rocket.
 
Last edited:
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Don't worry about the rocket itself. You only care about what it does. It applies a constant force over a specified time? How does this affect the astronaut in terms of momentum?
 
difference of momentum= (100N)(2.0s) = 200kgm/s

200kgm/s= (1960N/ 9.8m/s^2) V

V=1m/s

I first found the difference of momentum which is force * time. then used the equation momentum=mass*velocity. Is this correct?
 
rtamplain said:
difference of momentum= (100N)(2.0s) = 200kgm/s

200kgm/s= (1960N/ 9.8m/s^2) V

V=1m/s

I first found the difference of momentum which is force * time. then used the equation momentum=mass*velocity. Is this correct?

Looks Good!:smile:
 

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