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**1. A ball weighing 520g is thrown straight up at 6.0m/s**

a) What is the initial momentum of the ball in N.s

a) What is the initial momentum of the ball in N.s

**2. p=mv**

**=520g(1kg/1000g)(6.0m/s)**

=3.12

=3.1 N.s

=3.12

=3.1 N.s

I don't see how this is correct because it takes kg.m.s^2 to create a Newton. There is none here.

Then we go on to

**B)What is the momentum when the ball is at peak?**

p=mv

=520g(1kg/1000g)(0 m/s)

=0 kg m/s

**C)What is the momentum of the ball when it hits the ground?**

No idea how to even go about doing C).. This one through me for a loop.

**D)What is the change in momentum as the ball comes back to its original position?**

P=m(Vf-Vi)

P=520g(1kg/1000g)(-6.0m/s - 6.0m/s)

=-6.24

=-6.2N.s

Any help be greatly appreciated. Thank you.