1. A ball weighing 520g is thrown straight up at 6.0m/s a) What is the initial momentum of the ball in N.s 2. p=mv =520g(1kg/1000g)(6.0m/s) =3.12 =3.1 N.s I don't see how this is correct because it takes kg.m.s^2 to create a Newton. There is none here. Then we go on to B)What is the momentum when the ball is at peak? p=mv =520g(1kg/1000g)(0 m/s) =0 kg m/s C)What is the momentum of the ball when it hits the ground? No idea how to even go about doing C).. This one through me for a loop. D)What is the change in momentum as the ball comes back to its original position? P=m(Vf-Vi) P=520g(1kg/1000g)(-6.0m/s - 6.0m/s) =-6.24 =-6.2N.s Any help be greatly appreciated. Thank you.