Momentum to Energy Conversion: Learn How it is Done

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Discussion Overview

The discussion revolves around the conversion of momentum expressed in MeV/c to energy, particularly in the context of accelerator physics. Participants explore the relationship between momentum and energy, discussing relevant equations and units.

Discussion Character

  • Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant seeks clarification on how to convert momentum in MeV/c to energy, questioning whether it involves simply multiplying by the speed of light (c).
  • Another participant presents a relationship between momentum, energy, and mass using the equation ##m^2 c^2=E^2/c^2-p^2##.
  • A different participant offers a mnemonic for remembering the relationship, stating ##E^2 = (pc)^2 + (mc^2)^2##, emphasizing that all terms have units of energy.
  • A later reply confirms that multiplying the momentum (0.79 MeV/c) by c results in an energy value of 0.79 MeV.

Areas of Agreement / Disagreement

Participants generally agree on the method of converting momentum to energy, but the discussion does not resolve all underlying assumptions or implications of the equations presented.

Contextual Notes

The discussion does not address potential limitations or assumptions in the equations used, nor does it clarify the context in which these conversions apply.

goodphy
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Hello.

I'm reading some accelerator physics paper showing the momentum unit for the accelerated particles as MeV/c.

I'm not interested in the momentum but energy thus I really want to convert this to energy.

How it is done? Simply multiplying c? if so, there must be some reason for justify the action.

Please help me to go further.
 
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Momentum, energy, and mass are related by ##m^2 c^2=E^2/c^2-p^2##
 
Or, the way I like to remember it: ##E^2 = (pc)^2 + (mc^2)^2##.

E, pc and mc2 all have units of energy (MeV or joules or whatever)
 
Oh thanks people!

Thus..since momentum in the paper is, for example, 0.79 MeV/c so pc should be simply the momentum multiplied by c, 0.79 MeV right?
 
Right.
 

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