Momentum transfer between d-electrons and the nucleus in ferromagnetism?

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SUMMARY

The discussion centers on the relationship between d-electrons and the nucleus in ferromagnetic materials, specifically iron, nickel, and cobalt. It establishes that the primary source of ferromagnetism is the alignment of unpaired d-orbital electrons, which significantly enhances the flux density of an external magnetic field. The conversation concludes that momentum transfer between d-orbitals and the nucleus is unlikely, as the intrinsic magnetic moment of protons is much smaller than that of electrons, rendering nuclear interactions negligible in the context of ferromagnetism. The discussion also emphasizes that ferromagnetism is unrelated to nuclear binding energy.

PREREQUISITES
  • Understanding of ferromagnetism and its principles
  • Knowledge of d-orbital electron behavior in magnetic fields
  • Familiarity with inductance and its effects in electrical circuits
  • Basic concepts of nuclear physics, particularly regarding isotopes
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  • Research the properties of ferromagnetic materials, focusing on iron, nickel, and cobalt
  • Study the principles of inductance and its mathematical formulations
  • Explore the role of d-orbitals in magnetic alignment and their impact on material properties
  • Investigate the differences between stable isotopes of iron, particularly Iron-56 and Iron-57
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metastable
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If a copper wire is wound around a piece of iron, nickel or cobalt, and a voltage is applied to the wire, it takes a longer amount of time for the current to reach its maximum value, than if the iron were replaced with a different material, such as glass— a phenomenon known as inductance. My understanding is within the ferromagnetic substance, the d-orbital electrons come into alignment with the external magnetic field, in a process which substantially increases the flux density of the externally applied field. I was wondering whether it is thought there is any momentum transfer between the d-orbitals and the nucleus causing or facilitating the inductance property? As I side note I was wondering this while playing with the close packing of magnetic spheres with the same # of spheres as common isotope numbers of cobalt, nickel and iron, as well as gadolinium, dysprosium and holmium. Specifically the radial symmetrical geometry for these specific #’s of spheres observed was bipyramid & truncated bipyramid.
 
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metastable said:
If a copper wire is wound around a piece of iron, nickel or cobalt, and a voltage is applied to the wire, it takes a longer amount of time for the current to reach its maximum value, than if the iron were replaced with a different material, such as glass— a phenomenon known as inductance. My understanding is within the ferromagnetic substance, the d-orbital electrons come into alignment with the external magnetic field, in a process which substantially increases the flux density of the externally applied field. I was wondering whether it is thought there is any momentum transfer between the d-orbitals and the nucleus causing or facilitating the inductance property? As I side note I was wondering this while playing with the close packing of magnetic spheres with the same # of spheres as common isotope numbers of cobalt, nickel and iron, as well as gadolinium, dysprosium and holmium. Specifically the radial symmetrical geometry for these specific #’s of spheres observed was bipyramid & truncated bipyramid.
The predominant source of ferromagnetism is the alignment of the intrinsic magnetic moment of unpaired electrons. This occurs easily only if the electron is unpaired in in the outer shell.
The intrinsic magnetic moment of the proton is very much smaller than that of the electron and interactions with the nucleus are tiny in this context. So I think the answer is "unlikely"
Do you have a table of the correlations you noticed? (i.e. data?)
 
hutchphd said:
Do you have a table of the correlations you noticed? (i.e. data?)

Only the close packing radial geometrical symmetry with the same number of spheres as nucleons in the ferromagnetic elements, and the observation that cobalt, nickel and iron (the only room temperature ferromagnetics) have the highest or nearly the highest binding energy and/or among the lowest mass per nucleon among all the elements.

https://www.mutah.edu.jo/eijaz/bindingenergymore.files/image002.gif
https://www.mutah.edu.jo/eijaz/bindingenergymore.files/image034.gif
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  1. Ferromagnetism has nothing to do with nuclear binding
  2. Your pictures of little spheres stuck together have nothing to do with nuclear structure
  3. Gadolinium is a ferromagnet at or near room temperature too
  4. Copper, one past nickel, is repelled by a magnetic field
 
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So if I understand correctly, when the D-orbitals realign under the influence of an external magnetic field, the nucleus is unaffected.
 
I just thought of one follow up question. Most “permanent magnets” contain iron, nickel or cobalt. If I understand correctly, one would say the nucleus is not rotationally affected when the D-orbitals realign under an external magnetic field. But what about when an entire permanent magnet “accelerates” along a vector under the influence of an external magnetic field... are the d orbitals transferring momentum to the nuclei in this case?
 
Your personal theory idea is still wrong.
 
Assuming you are correct, if an experiment was done in which the inductance of the same copper solenoid was compared between being wound around either a pure Iron-56 or pure Iron-57 magnetic core, we shouldn’t expect to observe any significant change in the inductance?
 
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How many times do I have to answer the same question? Ferromagnetism has nothing to do with nuclear binding. Once is a question, the second time is a personal theory, but by the third time it's getting close to crackpottery.
 
  • #10
I’m sorry I thought it was a different question. The reason I asked about Iron-57 compared to Iron 56 is:

“Of these stable isotopes, only 57Fe has a nuclear spin (−1⁄2).”
https://en.m.wikipedia.org/wiki/Iron
&

“inductance is also equal to the ratio of magnetic flux to current[11][12][13][14]
https://en.m.wikipedia.org/wiki/Inductance
{\displaystyle L={\Phi (i) \over i}}


&

“The intrinsic magnetic moment μ of a spin 1/2particle with charge q, mass m, and spin angular momentum S, is[10]
https://en.m.wikipedia.org/wiki/Spin_(physics)
\boldsymbol{\mu} = \frac{g_s q}{2m} \mathbf{S}
 
  • #11
No matter how many times you ask, and how many irrelevant posts you make, the answer is still "Ferromagnetism has nothing to do with nuclear binding. "
 
  • #12
Vanadium 50 said:
"Ferromagnetism has nothing to do with nuclear binding."
I think this answers the question, so there is no point in discussing it any further.

Thread closed.
 

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