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A Momentum transfer perpendicular to velocity of proton?

  1. Aug 15, 2017 #1
    An assumption in deducing the Bethe equation is that the momentum transfer is perpendicular to the direction of the particle.


    In Allison & Cobb (1980), just after eq. 28, they state that the first two terms of the Photoabsorption Ionization model arise from the magnetic vector potential in the Coulomb gauge, for which the electric field is transverse to the direction of 3-momentum transfer.

    I know that the magnetic vector potential A is in units of momentum per charge, so ignoring hard collisions, how does the justification of this look?
  2. jcsd
  3. Aug 20, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
  4. Aug 24, 2017 #3


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