Monopole Moment of a sphere of charge

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SUMMARY

The discussion focuses on calculating the monopole moment of a continuous charge distribution defined by the surface charge density \(\sigma = \text{const} \cdot \cos(\theta)\). The participant attempts to use the formula \(p = \int r' \sigma \, da\) but encounters issues with the integration leading to a zero result. It is confirmed that the monopole moment is equivalent to the total charge, which in this case is zero due to the symmetry of the charge distribution. The participant acknowledges the mistake in their approach, particularly in confusing monopole and dipole moment calculations.

PREREQUISITES
  • Understanding of surface charge density and its mathematical representation.
  • Familiarity with spherical coordinates and their integration.
  • Knowledge of monopole and dipole moments in electrostatics.
  • Proficiency in performing double integrals in calculus.
NEXT STEPS
  • Review the concept of monopole moments in electrostatics.
  • Study the derivation and application of surface charge density formulas.
  • Practice double integrals in spherical coordinates for various charge distributions.
  • Explore the differences between monopole and dipole moments in physics.
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone involved in solving problems related to charge distributions and their moments.

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Homework Statement



I'm really bad at these type of problems. I'm supposed to find the monopole moment of this continuous charge distribution. its charge is

\sigma = const*cos(\theta)

Homework Equations



p = \int r'\rho(r')d\tau
which then since we are doing a surface charge should be
p = \int r' \sigma da

The Attempt at a Solution


Well, I want to do the double integral of something to find the charge distribution so I can find the monopole moment. I'm thinking something like
p = \int_{0}^{2 \pi}\int_{0}^{2 \pi} r' * c \cdot cos(\theta) sin( \theta) r^2 d\phi d\theta
and I'm thinking that r' is just r so then it would be

p = \int_0^{2\pi} d\phi \int_0^{\pi} r'^3cose(\theta)sin(\theta)d\theta
 
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The obvious problem that then comes up is that then appears is that I get a 0 term from the second integral that makes my whole monopole moment zero. Is this correct?
 
if you are supposed to calculate the monopole moment then you integrate the charge density only. the formulas you have above are those for a dipole moment. monopole moment is just total charge
 
The monopole moment is zero. Some of your formulas are wrong, as Capt. pointed out.
 
Ok, thanks! I think I see what I did wrong!
 

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