Monopole Moment of a sphere of charge

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Homework Help Overview

The problem involves calculating the monopole moment of a continuous charge distribution defined by a surface charge density that varies with the angle, specifically \(\sigma = \text{const} \cdot \cos(\theta)\). Participants are exploring the implications of this charge distribution on the monopole moment.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration process needed to find the monopole moment, with one attempting to set up a double integral involving the charge density. There is a question raised about the implications of obtaining a zero result from the integration.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the distinction between monopole and dipole moments. There is acknowledgment of potential errors in the formulas used, and one participant expresses a realization of their mistake.

Contextual Notes

Participants are navigating the complexities of integrating a non-uniform charge distribution and are questioning the assumptions underlying their calculations. There is a focus on ensuring the correct application of formulas relevant to monopole moments.

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Homework Statement



I'm really bad at these type of problems. I'm supposed to find the monopole moment of this continuous charge distribution. its charge is

[tex]\sigma = const*cos(\theta)[/tex]

Homework Equations



[tex]p = \int r'\rho(r')d\tau[/tex]
which then since we are doing a surface charge should be
[tex]p = \int r' \sigma da[/tex]

The Attempt at a Solution


Well, I want to do the double integral of something to find the charge distribution so I can find the monopole moment. I'm thinking something like
[tex]p = \int_{0}^{2 \pi}\int_{0}^{2 \pi} r' * c \cdot cos(\theta) sin( \theta) r^2 d\phi d\theta[/tex]
and I'm thinking that r' is just r so then it would be

[tex]p = \int_0^{2\pi} d\phi \int_0^{\pi} r'^3cose(\theta)sin(\theta)d\theta[/tex]
 
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The obvious problem that then comes up is that then appears is that I get a 0 term from the second integral that makes my whole monopole moment zero. Is this correct?
 
if you are supposed to calculate the monopole moment then you integrate the charge density only. the formulas you have above are those for a dipole moment. monopole moment is just total charge
 
The monopole moment is zero. Some of your formulas are wrong, as Capt. pointed out.
 
Ok, thanks! I think I see what I did wrong!
 

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