Moon Gravitational Force Problem

[fewill]

1. In tests on Earth a lunar surface exploration vehicle (mass = 5.68 × 103 kg) achieves a forward acceleration of 0.220 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.42 × 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon?
G= 6.673*10^-11
mEarth= 5.98*10²⁴
mMoon= 7.35*10²²
rEarth= 6.38*10⁶
rMoon= 1.74*10⁶

2. F=Gm₁m₂/r²


3. All I know is that the mass is the same on Earth as it is on the moon. I figured that the frictional force is the opposite of the driving force. I am lost. Please help.

 

[Hootenanny]

1. In tests on Earth a lunar surface exploration vehicle (mass = 5.68 × 103 kg) achieves a forward acceleration of 0.220 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.42 × 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon?
G= 6.673*10^-11
mEarth= 5.98*10²⁴
mMoon= 7.35*10²²
rEarth= 6.38*10⁶
rMoon= 1.74*10⁶

2. F=Gm₁m₂/r²


3. All I know is that the mass is the same on Earth as it is on the moon. I figured that the frictional force is the opposite of the driving force. I am lost. Please help.

I'll give you a hint: this question has nothing to do with Newton's law of gravitation, but everything to do with Newton's Second Law

 

[fewill]

So do I use F-fk=ma?

 

[Hootenanny]

So do I use F-fk=ma?

Sounds good to me

 

[fewill]

Got it thanks!

 

[Hootenanny]

Got it thanks!

A pleasure.