Motion in a Plane Questions: Height, Distance, Velocity

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Homework Help Overview

The discussion revolves around a physics problem involving a firefighter climbing a ladder leaning against a wall. The problem includes determining the height of the wall, the distance from the base of the ladder to the wall, and the firefighter's average vertical velocity. The context is rooted in motion in a plane, specifically dealing with trigonometric relationships and kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of trigonometric functions to find the height of the wall and the distance from the wall. There are attempts to clarify the difference between average vertical velocity and resultant velocity. Some participants question the original poster's use of a 10m ladder instead of the stated 100m, leading to discussions about potential typos and assumptions in the problem setup.

Discussion Status

The conversation is ongoing, with participants providing feedback on calculations and methods. Some guidance has been offered regarding the interpretation of vertical distance and velocity, but there is no explicit consensus on the correct values or methods being used. Multiple interpretations of the problem are being explored.

Contextual Notes

There is a noted discrepancy regarding the length of the ladder, with some participants suggesting that the original post may contain a typo. The discussion also highlights the importance of significant digits in calculations and the assumptions made about the ladder's position relative to the wall.

pharm89
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Homework Statement



Hi, I have some answers to the following questions but I would just like to know if I am understanding the concepts correctly.

A firefighter climbs up a 100 m ladder leaning against a vertical wall. The ladder makes an angle of 25 degrees with the wal. The firefighter reaches th eroof in 15 seconds.
(a) what is the height of the wall?
(b) how far is the base of the ladder from the wall?
(c) what is the firefighters average vertical velocity?

Homework Equations


Pythagorean Theorum - (a^2) + (b^2) = c^2
velocity (v) = distance/time


The Attempt at a Solution



(a) COS = adjacent/hypotenuse
Cos25 degrees = X/10 m
0.91 = x/10m
X= 9.06 m

(b) a^2 +b^2 = c^2
a^2 + (9.06)^2 = 10^2
a^2 +82.08 = 100
a^2 = 17.92
a= 4.2 m

(c) given distance up ladder = 10 m
time = 15.0 seconds
Required: velocity
Analysis: velocity = distance/time =10m/15s = 0.666 m/s

what is the difference between average vertical velocity and resultant velocity?
THanks for the help
Pharm 89
 
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pharm89 said:

Homework Statement



Hi, I have some answers to the following questions but I would just like to know if I am understanding the concepts correctly.

A firefighter climbs up a 100 m ladder leaning against a vertical wall. The ladder makes an angle of 25 degrees with the wal. The firefighter reaches th eroof in 15 seconds.
(a) what is the height of the wall?
(b) how far is the base of the ladder from the wall?
(c) what is the firefighters average vertical velocity?

Since you've used 10m in your calculations, I presume this is a typo.

The Attempt at a Solution



(a) COS = adjacent/hypotenuse
Cos25 degrees = X/10 m
0.91 = x/10m
X= 9.06 m
Method correct.. I don't have a calculator to check your maths though. Also, this is correct, if we make the asumption that the ladder reaches the very top of the building, which we must make here.

(b) a^2 +b^2 = c^2
a^2 + (9.06)^2 = 10^2
a^2 +82.08 = 100
a^2 = 17.92
a= 4.2 m
Again, correct method

(c) given distance up ladder = 10 m
time = 15.0 seconds
Required: velocity
Analysis: velocity = distance/time =10m/15s = 0.666 m/s

what is the difference between average vertical velocity and resultant velocity?

You have calculated the resultant velocity. The vertical velocity will be v=(vertical distance)/(time)
 
cristo said:
Since you've used 10m in your calculations, I presume this is a typo.

Method correct.. I don't have a calculator to check your maths though. Also, this is correct, if we make the asumption that the ladder reaches the very top of the building, which we must make here.


Again, correct method



You have calculated the resultant velocity. The vertical velocity will be v=(vertical distance)/(time)

Thanks for your help. So therefore for part c they are asking for the average vertical velocty...would that be the same answer though??
vertical distance = 10 m/15 seconds = 0.666m/s
 
pharm89 said:
Thanks for your help. So therefore for part c they are asking for the average vertical velocty...would that be the same answer though??
vertical distance = 10 m/15 seconds = 0.666m/s

No, the vertical distance is what you calculated in (a) i.e. the height of the building. Draw a diagram, you'll see that the length of the ladder, 10m, is not a vertical distance!
 
cristo said:
No, the vertical distance is what you calculated in (a) i.e. the height of the building. Draw a diagram, you'll see that the length of the ladder, 10m, is not a vertical distance!

Yes, that makes sense...vertical distance = 9.06 m/15 seconds = 0. 6 m/s
Thanks for the assistance.
Pharm 89
 
10m? Wasn't it supposed to be 100m?

I took

[tex] <br /> sin(25)*100m=40m<br /> [/tex]

[tex] <br /> cos(25)*100m=90m<br /> [/tex]

Instead of doing it the hard way without going through Pythogarous and keeping the idea of significant digits in my head.

And no tough work involved here...

[tex] <br /> 40m/15s = 3 m/s<br /> [/tex]

Got 3 m/s, which isn't the same as you'lls (The Texan accent triumphs again)

But pharm89, where did the 10m instead of the 100m come from?

Please be careful in calculations.
 
Last edited:
:bugeye: A 100m ladder :bugeye:
 
MadScientist 1000 said:
[tex] <br /> sin(25)*100m=40m<br /> [/tex]

There is no reason to round off 100*sin(25) = 42.26 to 40.
 
MadScientist 1000 said:
10m? Wasn't it supposed to be 100m?

I took

[tex] <br /> sin(25)*100m=40m<br /> [/tex]

[tex] <br /> cos(25)*100m=90m<br /> [/tex]

Instead of doing it the hard way without going through Pythogarous and keeping the idea of significant digits in my head.

And no tough work involved here...

[tex] <br /> 40m/15s = 3 m/s<br /> [/tex]

Got 3 m/s, which isn't the same as you'lls (The Texan accent triumphs again)

But pharm89, where did the 10m instead of the 100m come from?

Please be careful in calculations.

I presumed (and was apparently right, as the poster didn't correct me) that there was a typo in the original post, and it should in fact be 10m. And, as Hootenanny points out, 100m is a little long for a ladder!
 
  • #10
At first I wondered why he shrunk the ladder from 100m to 10m in his calcs.

But 10m has to be the correct size. Can you imagine climbing 100m in 15s?
 

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