A rocket is launched from level ground with a speed of 30.0 m/s at an angle of 40 degrees above the horizontal. Find:
a) Maximum height reached by the rocket.
b) The time rocket is in the air.
c) the horizontal distance where the rocket lands.
V= Vo + at
V^2 = Vo^2 + 2a(X-Xo)
X= Xo +Vo(t) + (1/2)at^2
The Attempt at a Solution
Divided the entire motion into two phases 1st and 2nd, Got x and y components of everything. Can't seem to find the time and final position anyway. I am not allowed to use the direct formula for Range and Height.