Motion of a Block with Three Forces

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The discussion focuses on calculating the motion of a block subjected to three forces on a frictionless surface. Participants clarify that to find the resultant force, one must break down each force into its x and y components and then sum these components. The resultant force is calculated, and there are discussions about ensuring the correct signs for the components. The magnitude of the resultant force is confirmed to be approximately 16.63 N, with further calculations needed for acceleration and motion over time. The conversation emphasizes the importance of using vector addition and trigonometric functions to solve the problem accurately.
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The diagram below shows a block of mass m=2.0\; \rm kg on a frictionless horizontal surface, as seen from above. Three forces of magnitudes F_1 = 4.0\;{\rm N}, F_2 = 6.0\;{\rm N}, and F_3 = 8.0\;{\rm N} are applied to the block, initially at rest on the surface, at angles shown on the diagram.

1. Calculate the magnitude of the total resultant force \vec{F}_{\rm r} = \vec{F}_1+ \vec{F}_2 +\vec{F}_3 acting on the mass.

2. What angle does F_r_vec make with the positive x axis?

3. What is the magnitude of the mass's acceleration vector, a_vec?

4. What is the direction of a_vec? In other words, what angle does this vector make with respect to the positive x axis?

5. How far (in meters) will the mass move in 5.0 s?

6. What is the magnitude of the velocity vector of the block at t = 5.0\;{\rm s}?

7. In what direction is the mass moving at time t = 5.0\;{\rm s}? That is, what angle does the velocity vector make with respect to the positive x axis?I just need clarification on how to start this problem...do I simply use Fnet = ma? and to find the resultant I am assuming I need the magnitude of vectors forumla, but how do I use it here?

any help will be greatly appreciated.
http://img216.imageshack.us/img216/6486/1206lb2.th.jpg
 
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fubag said:
I just need clarification on how to start this problem...do I simply use Fnet = ma?
Sure.
and to find the resultant I am assuming I need the magnitude of vectors forumla, but how do I use it here?
Just find the components of each force and add them up.
 
Hint to start with. Break down the forces into their x and y components. Then find the resultant force from these. Rember you'll need to make use of the sin and cos of your angles.
 
ok

so this is what I got:

f(->)1: 3.63i + 1.69j
f(->)2: 4.91i - 3.44j
f(->)3: 8i

Now to determine the resultant, I just add all of these up?

I get then f(->)r: 16.54i - 1.75j

so resultant magnitude is = 16.63 N??
 
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Add up the components and you have the components of the resultant. (Double check the signs of your components.)
 
ok sorry

the 3rd one has -8iSo then it should be 1.83 N?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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