- #1
debjit625
- 40
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Hi everybody
I got this from a book
A stone is dropped from a height of 50 m and it falls freely. Calculate the velocity of the stone when it reaches the ground.
Assuming g = - 9.8 ms2 ,negative as its going downwards .
Using v2 = u2 + 2a(x - x0)
v2 = 02 + 2(-9.8)(-50-0)
I got v = 31.30 ms1
But the book have an answer of 9.9 ms1
so what's wrong with my process or the answer of the book is wrong ?
Thanks
I got this from a book
A stone is dropped from a height of 50 m and it falls freely. Calculate the velocity of the stone when it reaches the ground.
Assuming g = - 9.8 ms2 ,negative as its going downwards .
Using v2 = u2 + 2a(x - x0)
v2 = 02 + 2(-9.8)(-50-0)
I got v = 31.30 ms1
But the book have an answer of 9.9 ms1
so what's wrong with my process or the answer of the book is wrong ?
Thanks