Motion problem Final velocity of a dropped stone

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Homework Help Overview

The problem involves calculating the final velocity of a stone dropped from a height of 50 meters under the influence of gravity, with a specific focus on the use of kinematic equations. The original poster presents their calculation and compares it to a provided answer from a textbook.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the kinematic equation v² = u² + 2a(x - x₀) to find the final velocity, questioning the discrepancy between their result and the textbook answer. Some participants discuss the choice of direction for acceleration due to gravity and its implications on the calculations.

Discussion Status

The discussion is ongoing, with participants exploring the validity of the original poster's calculations and the potential for a typo in the textbook. There is also a note regarding the proper categorization of the question within the forum.

Contextual Notes

Participants mention that the problem is not formally assigned as homework, but it is suggested that textbook problems should be posted in the Homework Help section. There is a reminder about the importance of using descriptive thread titles for clarity.

debjit625
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Hi everybody

I got this from a book

A stone is dropped from a height of 50 m and it falls freely. Calculate the velocity of the stone when it reaches the ground.

Assuming g = - 9.8 ms2 ,negative as its going downwards .

Using v2 = u2 + 2a(x - x0)

v2 = 02 + 2(-9.8)(-50-0)

I got v = 31.30 ms1

But the book have an answer of 9.9 ms1

so what's wrong with my process or the answer of the book is wrong ?

Thanks
 
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debjit625 said:
Hi everybody

I got this from a book

A stone is dropped from a height of 50 m and it falls freely. Calculate the velocity of the stone when it reaches the ground.

Assuming g = - 9.8 ms2 ,negative as its going downwards .

Using v2 = u2 + 2a(x - x0)

v2 = 02 + 2(-9.8)(-50-0)

I got v = 31.30 ms1

But the book have an answer of 9.9 ms1

so what's wrong with my process or the answer of the book is wrong ?

Thanks

Careful picking your directions.

g = 9.8 m/s2 [Down] = -9.8 m/s2 [Up]

Your answer is correct though, maybe the book had a typo.
 
@Zondrina
I learned its a free choice i.e.. I can choose my positive and negative direction..
Yes it make sense that acceleration due to gravity is always downwards so that's its positive direction,but again mathematically I can choose it negative,if I see the motion in a Cartesian coordinate system.Am I wrong ?

Thanks

I found a notice,its not a homework so I didn't posted it in homework section.
 
debjit625 said:
@Zondrina
I found a notice,its not a homework so I didn't posted it in homework section.

At the PF, all schoolwork-type questions need to go in the Homework Help (HH) forums. You should also use the HH Template when you post such questions (it is provided for you when you start a new HH thread) -- the Template helps to organize the way you present the question and your work on the solution.

Here is the text from your Notice:

Please post homework problems and textbook problems in the homework forums. Even if you're just self-studying and not taking a formal course, problems from textbooks always belong in the homework forums. I have moved it for you.

And here is a thread that should help you understand why the PF HH rules are the way they are:

https://www.physicsforums.com/showthread.php?t=373889

:smile:
 
Oh, and we ask that you please use very descriptive thread titles, to make it easier for other folks on the forum to decide if they are interested in clicking into your thread. I have added some more descriptive words to your thread title. Cheers! :smile:
 

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